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Ray Of Light [21]
3 years ago
10

Which transformation of Figure A results in Figure A'? a reflection across the y-axis a reflection across the x-axis a clockwise

rotation of 90° about the origin a translation 12 units right and 2 units down.
Mathematics
1 answer:
Studentka2010 [4]3 years ago
6 0

Is there a picture of the problem you can add to this?

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In a population of 10,000, there are 5000 nonsmokers, 2500 smokers of one pack or less per day, and 2500 smokers of more than on
Kazeer [188]

Answer:

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

Step-by-step explanation:

We have to write the transition matrix M for the population.

We have three states (nonsmokers, smokers of one pack and smokers of more than one pack), so we will have a 3x3 transition matrix.

We can write the transition matrix, in which the rows are the actual state and the columns are the future state.

- There is an 8% probability that a nonsmoker will begin smoking a pack or less per day, and a 2% probability that a nonsmoker will begin smoking more than a pack per day. <em>Then, the probability of staying in the same state is 90%.</em>

-  For smokers who smoke a pack or less per day, there is a 10% probability of quitting and a 10% probability of increasing to more than a pack per day. <em>Then, the probability of staying in the same state is 80%.</em>

- For smokers who smoke more than a pack per day, there is an 8% probability of quitting and a 10% probability of dropping to a pack or less per day. <em>Then, the probability of staying in the same state is 82%.</em>

<em />

The transition matrix becomes:

\begin{vmatrix} &NS&P1&PM\\NS&  0.90&0.08&0.02 \\  P1&0.10&0.80 &0.10 \\  PM& 0.08 &0.10&0.82 \end{vmatrix}

The actual state matrix is

\left[\begin{array}{ccc}5,000&2,500&2,500\end{array}\right]

We can calculate the next month state by multupling the actual state matrix and the transition matrix:

\left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4950&2650&2400\end{array}\right]

In one month, we will have 4,950 non-smokers, 2,650 smokers of one pack and 2,400 smokers of more than one pack.

To calculate the the state for the second month, we us the state of the first of the month and multiply it one time by the transition matrix:

\left[\begin{array}{ccc}4950&2650&2400\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] =\left[\begin{array}{ccc}4912&2756&2332\end{array}\right]

In two months, we will have 4,912 non-smokers, 2,756 smokers of one pack and 2,332 smokers of more than one pack.

If we repeat this multiplication 12 times from the actual state (or 10 times from the two-months state), we will get the state a year from now:

\left( \left[\begin{array}{ccc}5000&2500&2500\end{array}\right] * \left[\begin{array}{ccc}0.90&0.08&0.02\\0.10&0.80 &0.10\\0.08 &0.10&0.82\end{array}\right] \right)^{12} =\left[\begin{array}{ccc}4792.63&3005.44&2201.93\end{array}\right]

In a year, we will have 4,793 non-smokers, 3,005 smokers of one pack and 2,202 smokers of more than one pack.

3 0
3 years ago
A brand new car is purchased for $45000 and depreciates by 8% per year. How much is it worth after?
RideAnS [48]
I=prt
i=(45000)(0.08)(1)
i=3600
depreciation= $3600/y
8 0
4 years ago
Heather walked 24 feet to the south and 32 feet to the east, but then she walked in a straight line back to where she started, a
Oksanka [162]

Answer:

96 feet

Step-by-step explanation:

This problem requires the use of pythagorean theorem.

she walks 24 ft south + 32 ft east + \sqrt{24^2 + 32^2} = 56 + \sqrt{1600} = 56 + 40 = 96

4 0
3 years ago
What's the lowest point of the graph of 10y + 30 = x?
inna [77]
The lowest must be ,,,,,when x=0
so
10y+30=0
10y=-30
y=-3
So your answer is (0, -3)
3 0
3 years ago
Assume a normal distribution. From the Baltimore facility, 145 samples were obtained and compared with a sample of 128 from the
Evgesh-ka [11]

Answer:

Hello your question has some missing part below is the missing part

The mean hours per week and standard deviations for middle management who had been with the organizations for approximately the same length of time were: Baltimore facility, Burlington facility Mean 52.5 Mean 39.7

Standard deviation 19.7 Standard Deviation 8.9Using this data, complete the following:

State your hypothesis and conduct a hypothesis testing using a significance of 0.10.

answer :  We will reject the Null hypothesis

Step-by-step explanation:

μ1 = mean working hours for Baltimore facility  

μ2 = mean working hours  for Burlington facility  

Hence the Hypothesis are :

H0 : μ1 = μ2

Ha : μ1  > μ2

<em>Next:  Conduct a hypothesis testing </em>

we will apply Z - testing attached below is the hypothesis testing

n1 = 145 , X1 = 52.5 , δ1 = 19.7  ( Baltimore )

n2 = 128, X2 = 39.7 , δ2 = 8.9 ( Burlington )

6 0
3 years ago
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