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satela [25.4K]
3 years ago
11

I need help please will give you 5 stars and good rating

Mathematics
2 answers:
Brums [2.3K]3 years ago
3 0

Answer:

Step-by-step explanation:

atroni [7]3 years ago
3 0

Answer:

x=12

Step-by-step explanation:

To solve for the variable, we must isolate the variable, which is x.

\sqrt{x+4} -3=1

3 is being subtracted from the square root of x+4. The inverse of subtraction is addition. Add 3 to both sides of the equation.

\sqrt{x+4} -3+3=1+3

\sqrt{x+4} =1+3

\sqrt{x+4} =4

The square root of x+4 is being taken. The inverse of a square root is a square. Square both sides of the equation.

(\sqrt{x+4})^2 =4^2

x+4=4^2

Evaluate the exponent.

4^2= 4*4=16

x+4=16

4 is being added to x. The inverse of addition is subtraction. Subtract 4 from both sides of the equation.

x+4-4=16-4

x=16-4

x=12

The solution to this equation is x=12.

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Answer:

1.benchmark fractions

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Step-by-step explanation:

Hope it helps!

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I need help please. I need the the discount and selling price. Thank you
salantis [7]

Answer:

<h2><u>15.12 is the discount</u></h2><h2><u>68.88 is the sell price</u></h2>

Step-by-step explanation:

When you are taking off percentages from numbers, you first want to make the percent a number. This step is super simple. Just divide the 18 by 100

This gets you 0.18

Now multiply

84 * 0.18 = 15.12

So 15.12 is the discount

Then take 84 and subtract 15.12

84 - 15.12 = 68.88

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5 0
3 years ago
For about $1 billion in new space shuttle expenditures, NASA has proposed to install new heat pumps, power heads, heat exchanger
11111nata11111 [884]

Answer:

The probability of one or more catastrophes in:

(1) Two mission is 0.0166.

(2) Five mission is 0.0410.

(3) Ten mission is 0.0803.

(4) Fifty mission is 0.3419.

Step-by-step explanation:

Let <em>X</em> = number of catastrophes in the missions.

The probability of a catastrophe in a mission is, P (X) = p=\frac{1}{120}.

The random variable <em>X</em> follows a Binomial distribution with parameters <em>n</em> and <em>p</em>.

The probability mass function of <em>X </em>is:

P(X=x)={n\choose x}\frac{1}{120}^{x}(1-\frac{1}{120})^{n-x};\x=0,1,2,3...

In this case we need to compute the probability of 1 or more than 1 catastrophes in <em>n</em> missions.

Then the value of P (X ≥ 1) is:

P (X ≥ 1) = 1 - P (X < 1)

             = 1 - P (X = 0)

             =1-{n\choose 0}\frac{1}{120}^{0}(1-\frac{1}{120})^{n-0}\\=1-(1\times1\times(1-\frac{1}{120})^{n-0})\\=1-(1-\frac{1}{120})^{n-0}

(1)

Compute the compute the probability of 1 or more than 1 catastrophes in 2 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{2-0}=1-0.9834=0.0166

(2)

Compute the compute the probability of 1 or more than 1 catastrophes in 5 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{5-0}=1-0.9590=0.0410

(3)

Compute the compute the probability of 1 or more than 1 catastrophes in 10 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{10-0}=1-0.9197=0.0803

(4)

Compute the compute the probability of 1 or more than 1 catastrophes in 50 missions as follows:

P(X\geq 1)=1-(1-\frac{1}{120})^{50-0}=1-0.6581=0.3419

6 0
3 years ago
Translate the following inequality into written language. 5x-6&lt;14
Scrat [10]
Five x minus six is less than fourteen
8 0
3 years ago
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