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Oksanka [162]
3 years ago
15

The outer edge of the dime is about 55mm. What is the approximate length of the radius?

Mathematics
1 answer:
lozanna [386]3 years ago
3 0
To find the approximate length of the radius, you will use the formula for finding the circumference of a circle and solve for the radius (r).

C = 2 x pi x r
55 = 2 x 3.14 x r
<u>55 </u>= <u>6.28 x r</u>
6.28   6.28
r = 9.2 mm

The approximate radius is 9.2 mm.
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2 years ago
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Joseph and Wendy were catching tadpoles. At first Wendy caught nine times three more than Joseph caught. Joseph was upset and re
Dmitriy789 [7]

Answer:

Joseph caught 7 tadpoles

Step-by-step explanation:

Let the number of tadpoles caught by Joseph be x

The number of tadpoles Wendy caught will be ;

9(x + 3)

After Joseph was upset, he released half of Wendy’s tadpole and then six times as many as Joseph caught swam away leaving Wendy with only three tadpoles left;

Hence, mathematically;

9(x + 3)/2 - 6x = 3

Multiply through be 2

9(x + 3) - 12x = 6

9x + 27 -12x = 6

9x -12x = 6-27

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x = 21/3

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6 0
3 years ago
Hannah is at the supermarket to buy carrots and potatoes. If she buys 2 pounds of carrots and 3 pounds of potatoes, it will cost
zhenek [66]

Answer:

Carrots cost $ 1.75 a pound which is more than potatoes cost.

Step-by-step explanation:

Let,

Carrots cost $ x per pound and potatoes cost $ y per pound.

Buying 2 pounds of carrots  and 3 pounds of potatoes will cost her

$ (2\times x + 3\times y)

and

Buying 4 pounds of carrots and 4 pounds of potatoes will cost her

$ (4\times x + 4\times y)

According to the question,

(2\times x + 3\times y) = 8-----(1)

(4\times x + 4\times y) = 13-----(2)

multiplying (1) by 2 we get,

(4\times x + 6\times y) = 16-----(3)

Deducting (2) from (3) we get,

2\times y = 3

⇒ y = \frac{3}{2} = 1.5------------------(4)

Putting value of y in (1) we get,

(2\times x = 8 - 3\times 1.5) = 3.5

⇒  x =\frac{3.5}{2} = 1.75 ------------(5)

8 0
3 years ago
Please find the exact length of the midsegment of trapezoid JKLM with vertices J(6, 10), K(10, 6), L(8, 2), and M(2, 2). Thank y
I am Lyosha [343]

Answer:

the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

Step-by-step explanation:

From the diagram attached below; we can see a graphical representation showing the mid-segment of the trapezoid JKLM. The mid-segment is located at the line parallel to the sides of the trapezoid. However; these mid-segments are X and Y found on the line JK and LM respectively from the graph.

Using the expression for midpoints between two points to determine the exact length of the mid-segment ; we have:

\mathbf{ YX = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2} }

\mathbf{ YX = \sqrt{(8-5)^2+(8-2)^2} }

\mathbf{ YX = \sqrt{(3)^2+(6)^2} }

\mathbf{ YX = \sqrt{9+36} }

\mathbf{ YX = \sqrt{45} }

\mathbf{ YX = \sqrt{9*5} }

\mathbf{ YX = 3 \sqrt{5} }

Thus; the exact length of the midsegment of trapezoid JKLM  = \mathbf{ = 3 \sqrt{5} } i.e 6.708 units on the graph

8 0
2 years ago
Last math question. 6th grade math
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Answer:

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2 years ago
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