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Pachacha [2.7K]
3 years ago
5

a rectangle swimming pool is 4 ft deep. one side of the pool is 2.5 times longer than the other. the amount of water needed to f

ill the swimming pool is 1960 cubic feet. find the dimensions of the pool. (find largest and smallest)
Mathematics
1 answer:
mojhsa [17]3 years ago
8 0

Find the are of the pool by dividing the volume by the depth:

1960 / 4 = 490

The pool is 490 square feet.


Area is found by multiplying the length by the width.

Let the width = X

We are told the length is 2.5X ( 2.5 times longer)


So we now have 2.5x * x = 490


2.5x * x = 2.5x^2


Now we have 2.5x^2 = 490


Divide both sides by 2.5:

x^2 = 490/2.5

x^2 = 196

find X by taking the square root of 196:

x = √196

x = 14


The width is 14 feet

The length is 2.5 * 14 = 35 feet

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Answer:

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Step-by-step explanation:

Information given

\bar X=2.55 represent the sample mean for the late time for a flight

\mu population mean

\sigma=12 represent the population deviation

n=76 represent the sample size  

Confidence interval

The best point of estimate for the true mean is:

\hat \mu = \bar X = 2.55

The confidence interval for the true mean is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}}   (1)

The Confidence level given is 0.95 or 95%, th significance would be \alpha=0.05 and \alpha/2 =0.025. If we look in the normal distribution a quantile that accumulates 0.025 of the area on each tail we got z_{\alpha/2}=1.96

Replacing we got:

2.55-1.96\frac{12}{\sqrt{76}}=-0.148    

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