Question

a rectangle swimming pool is 4 ft deep. one side of the pool is 2.5 times longer than the other. the amount of water needed to fill the swimming pool is 1960 cubic feet. find the dimensions of the pool. (find largest and smallest)

Answer 1

Find the are of the pool by dividing the volume by the depth:

1960 / 4 = 490

The pool is 490 square feet.

Area is found by multiplying the length by the width.

Let the width = X

We are told the length is 2.5X ( 2.5 times longer)

So we now have 2.5x * x = 490

2.5x * x = 2.5x^2

Now we have 2.5x^2 = 490

Divide both sides by 2.5:

x^2 = 490/2.5

x^2 = 196

find X by taking the square root of 196:

x = √196

x = 14

The width is 14 feet

The length is 2.5 * 14 = 35 feet