1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anna [14]
2 years ago
14

Which equation choice could represent the graph shown below?

Mathematics
1 answer:
balu736 [363]2 years ago
8 0
(X+6)x(x-6)

You can look at the roots, which are -6, 0, and 6.
You might be interested in
How to determine the smallest absolute value
alexandr1967 [171]
The absolute value is basically the distance from zero, and distance is ALWAYS positive. After you removed your negatives, you need to just compare the values. For example. The smallest absolute value between -27 and 19 is 19. Hope this helped!
7 0
3 years ago
In an Algebra II class with 135 students, the final exam scores have a mean of 72.3 and standard deviation 6.5. The exams on the
gregori [183]
Population = 135 students
Mean score = 72.3
Standard deviation of the scores = 6.5

Part (a): Students from 2SD and 3SD above the mean
2SD below and above the mean includes 95% of the population while 3SD includes 99.7% of the population.
95% of population = 0.95*135 ≈ 129 students
99.7% of population = 0.997*135 ≈ 135 students

Therefore, number of students from 2SD to 3SD above and below the bean = 135 - 129 = 6 students.
In this regard, Students between 2SD and 3SD above the mean = 6/2 = 3 students

Part (b): Students who scored between 65.8 and 72.3
The first step is to calculate Z values
That is,
Z = (mean-X)/SD
Z at 65.8 = (72.3-65.8)/6.5 = 1
Z at 72.3 = (72.3-72.3)/6.5 = 0
Second step is to find the percentages at the Z values from Z table.
That is,
Percentage of population at Z(65.8) = 0.8413 = 84.13%
Percentage of population at (Z(72.3) = 0.5 = 50%
Third step is to calculate number of students at each percentage.
That is,
At 84.13%, number of students = 0.8413*135 ≈ 114
At 50%, number of students = 0.5*135 ≈ 68

Therefore, students who scored between 65.8 and 72.3 = 114-68 = 46 students
4 0
3 years ago
Courtney has a total of 88 stamps worth $15.56. Some are $0.25 stamps and some are $0.02 stamps. How many of each foes she have?
olganol [36]

Let x = # of 25-cent stamps

y = # of 2-cent stamps

{   x+ y = 88

{ 0.25x + 0.02y = 15.56

60 25-cent stamps 28 2-cent stamps

5 0
2 years ago
Jordan is another employee at the same coffee shop. He has worked there longer than Gabe and earns $3 more per hour than gabe
mel-nik [20]

Answer:

- Gabe earns 13.5 per hour

x ------------------ 4  ---- 8 --------- 12 ------ 16

Earnings ----- 57 ---- 111 ------- 165------ 219

Step-by-step explanation:

5 0
2 years ago
The volume of the right triangular prism is 91.8ft. The height of the prism is 10.8ft. What is the area of each base? Show your
kaheart [24]

Answer:

8.5 ft.

Step-by-step explanation:

We'll use this right triangular prism volume formula: base area x height = volume

base area = ?

length = 10.8

volume = 91.8

base area x 10.8 = 91.8

Divide both sides by 10.8

base area x 10.8/10.8 = 91.8/10.8

base area = 8.5

4 0
2 years ago
Other questions:
  • A textbook search committee is considering 18 books for possible adoption. The committee has decided to select 4 of the 18 for f
    7·1 answer
  • In the fraction 5/8, what is the term used to designate the 5?
    8·2 answers
  • 2<br> (m-n) <br> Answer this question knowwwww
    9·1 answer
  • HELPPPPP it's an emergency
    13·1 answer
  • THIS IS MY 3RD TIME POSTING THIS ANSWER PLSSSSSSSS 50 POINTSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSSS
    6·2 answers
  • A park bench is located 16 3/4 feet due north of an elm tree a fountain is located 9 1/2 feet due south of the same elm tree
    13·2 answers
  • 0.1784 to 2 decimal places
    12·1 answer
  • Given m Please help me I’m in need!!
    14·1 answer
  • Find R if p = 1.5 and R = (1400 – 500p)p<br> R=?
    14·1 answer
  • Pls help math problem pls
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!