All categories

4 years ago

How many hundredths are there in 0.563

2 answers:

7 0

There are 5 tenths, 6 hundredths, and 3 thousandths. The first decimal is the tenths, the second decimal is the hundredths, and the third decimal is the thousandths.

zloy xaker [14]4 years ago

4 0

The hundredths are represented by the number at the second decimal place.

So its 6 hundredths.

You might be interested in

A hotel manager is adding a tile border around the hotel's rectangular pool. Let p represent the width of the pool, in feet. T

Ronch [10]

Answer:

A and F

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

I need to Match each equation that represents each situation.

almond37 [142]

Step-by-step explanation:

this is quite easy, when you use just common sense and identify the right numbers and variable names.

they is nothing special needed, you don't even need to create the equations yourself.

$4.99 per pound. buys b pounds and pays $14.95.

14.95 = 4.99 × b

$4.99 per pound. buys b pounds and pays c.

this is exactly the same as before, just that this time the total amount is not given as a constant but as a variable.

c = 4.99 × b

d dollars per pound. buys b pounds and pays t.

the same as the 2 cases before, just now everything is a variable. no more constants, but otherwise the completely same structure and method.

t = d × b

earned $275, which is $45 more than Noah ("n").

$275 = n + $45

earned m dollars, which is $45 more than Noah ("n").

m = n + $45

earned m dollars, which is y dollars more than Noah (we are asked that Noah's earnings are now called "v").

here your teacher made a mistake.

sure, the only remaining answer is

v = m + y

but it is not correct. given the names of the prime and associated variables the correct answer would be

m = v + y or v = m - y

7 0

2 years ago

What is the set fee, or initial value, of this function

Ber [7]

Answer:
The set fee would be $15

Explanation:
The set fee is the starting value. This means that it is the value of the y at x = 0 (y-intercept).

To get the set fee, we would first need to get the equation of the line.

Equation of the linear line has the following general formula:
y = mx + c
where m is the slope and c is the y-intercept

1- getting the slope:
we are given two points which are:
(20,25) and (50,40)
the slope = $\frac{y2-y1}{x2-x1}= \frac{40-25}{50-20} = 0.5$

The equation now is:
y = 0.5x + c

2- getting the value of the y-intercept:
To get the value of the c, we will use any of the given points, substitute in the equation and solve for c.
I will choose the point (20,25)
y = 0.5x + c
25 = 0.5(20) + c
25 = 10 + c
c = 15

The equation of the line representing the scenario is:
y = 0.5x + 15

Now, we know that the value of the c is the y-intercept which is the initial value of the function at x=0.
In our situation, this represents the set fee.

Hope this helps :)

6 0

4 years ago

If f(x) = 1/4x+14, then f-1(x)=

makvit [3.9K]

Answer:

Step-by-step explanation:

-x+1/4×+14

6 0

3 years ago

Suppose there are 4 defective batteries in a drawer with 10 batteries in it. A sample of 3 is taken at random without replacemen

SSSSS [86.1K]

Answer:

a.) 0.5

b.) 0.66

c.) 0.83

Step-by-step explanation:

As given,

Total Number of Batteries in the drawer = 10

Total Number of defective Batteries in the drawer = 4

⇒Total Number of non - defective Batteries in the drawer = 10 - 4 = 6

Now,

As, a sample of 3 is taken at random without replacement.

a.)

Getting exactly one defective battery means -

1 - from defective battery

2 - from non-defective battery

So,

Getting exactly 1 defective battery = ⁴C₁ × ⁶C₂ = $\frac{4!}{1! (4 - 1 )!}$ × $\frac{6!}{2! (6 - 2 )!}$

= $\frac{4!}{(3)!}$ × $\frac{6!}{2! (4)!}$

= $\frac{4.3!}{(3)!}$ × $\frac{6.5.4!}{2! (4)!}$

= $4$ × $\frac{6.5}{2.1! }$

= $4$ × $15$ = 60

Total Number of possibility = ¹⁰C₃ = $\frac{10!}{3! (10-3)!}$

= $\frac{10!}{3! (7)!}$

= $\frac{10.9.8.7!}{3! (7)!}$

= $\frac{10.9.8}{3.2.1!}$

= 120

So, probability = $\frac{60}{120} = \frac{1}{2} = 0.5$

b.)

at most one defective battery :

⇒either the defective battery is 1 or 0

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 0 , then 3 non defective

Possibility = ⁴C₀ × ⁶C₃

= $\frac{4!}{0! (4 - 0)!}$ × $\frac{6!}{3! (6 - 3)!}$

= $\frac{4!}{(4)!}$ × $\frac{6!}{3! (3)!}$

= 1 × $\frac{6.5.4.3!}{3.2.1! (3)!}$

= 1× $\frac{6.5.4}{3.2.1! }$

= 1 × 20 = 20

getting at most 1 defective battery = 60 + 20 = 80

Probability = $\frac{80}{120} = \frac{8}{12} = 0.66$

c.)

at least one defective battery :

⇒either the defective battery is 1 or 2 or 3

If the defective battery is 1 , then 2 non defective

Possibility = ⁴C₁ × ⁶C₂ = 60

If the defective battery is 2 , then 1 non defective

Possibility = ⁴C₂ × ⁶C₁

= $\frac{4!}{2! (4 - 2)!}$ × $\frac{6!}{1! (6 - 1)!}$

= $\frac{4!}{2! (2)!}$ × $\frac{6!}{1! (5)!}$

= $\frac{4.3.2!}{2! (2)!}$ × $\frac{6.5!}{1! (5)!}$

= $\frac{4.3}{2.1!}$ × $\frac{6}{1}$

= 6 × 6 = 36

If the defective battery is 3 , then 0 non defective

Possibility = ⁴C₃ × ⁶C₀

= $\frac{4!}{3! (4 - 3)!}$ × $\frac{6!}{0! (6 - 0)!}$

= $\frac{4!}{3! (1)!}$ × $\frac{6!}{(6)!}$

= $\frac{4.3!}{3!}$ × 1

= 4×1 = 4

getting at most 1 defective battery = 60 + 36 + 4 = 100

Probability = $\frac{100}{120} = \frac{10}{12} = 0.83$

3 0

3 years ago