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2 years ago

What is the solution to the equation below round your answer to two decimal decimal places log4 x=2.1

Mathematics

1 answer:

nekit [7.7K]2 years ago

8 0

Answer:

Step-by-step explanation:

log4x = 2.1

logx/log4 = 2.1

logx = log(4) x 2.1

logx = 1.264

x = 10^(1.264)

x = 18.38 (to two d.p)

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2 years ago

Read 2 more answers

1.Encuentra la ecuación de la circunferencia que tiene como ecuación ordinaria (x-4)² + (y+5)²= 25 2- encuentra la ecuación gene

rodikova [14]

Responder:

1) x² + y²-8x + 10y + 16 = 0

2) x² + y² + x + 18y + 33 = 0

Explicación paso a paso:

A partir de la pregunta, debemos expresar la ecuación en la forma estándar de un círculo expresado como;

x² + y² + 2gx + 2fy + c = 0 donde;

(-g, -f) es el centro.

1) Para la ecuación (x-4) ² + (y + 5) ² = 25

Expande el paréntesis;

(x-4) ² + (y + 5) ² = 25

x²-8x + 16 + y² + 10x + 25 = 25

x²-8x + 16 + y² + 10y + 25-25 = 0

Recopile términos similares;

x² + y²-8x + 10y + 16 + 0 = 0

x² + y²-8x + 10y + 16 = 0

Por lo tanto, la ecuación requerida es x² + y²-8x + 10y + 16 = 0

2) Para la expresión (x + 1) ² + (y + 9) ² = 49

x² + x + 1 + y² + 18y + 81 = 49

x² + x + 1 + y² + 18y + 81-49 = 0

Recopile términos similares;

x² + y² + x + 18y + 82-49 = 0

x² + y² + x + 18y + 33 = 0

Por tanto, la ecuación requerida es x² + y² + x + 18y + 33 = 0

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2 years ago

How do you do this? Please give an example to #1 and explain thoroughly please. I have asked multiple times and gotten answers I

liberstina [14]

Answer:

y=2x

Step-by-step explanation:

y = kx is the format of the graph we are looking for (as told in the instructions) where k is the variable we are supposed to find (like y = x, y=2x, y=3x, etc)

Note that as x increases by 1, y increases by 2. We can see that by writing a table of the points of points that the line given intersects (picture below). We can see that by the values of the x-axis and the y-axis. Why does this happen? This is because y =2x for each value of x. We notice that in our table.

Therefore, the equation is y=2x. I hope this helps! If you still have questions, ask me in the comments!

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3 years ago