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kicyunya [14]
4 years ago
11

You inoculate a bacterium into three tubes of nutrient broth medium containing added salt: 0.5 percent NaCl, 5 percent NaCl, and

15 percent NaCl. After incubation, you notice significant turbidity in the 15 percent NaCl medium and modest turbidity in the 5 percent NaCl medium. There is no growth in the third tube. This organism would be termed ______.
a. halophilic
b. osmophobic
c. haloduric
d. barophilic
Biology
1 answer:
jenyasd209 [6]4 years ago
4 0

Answer:

a. halophilic

Explanation:

Halophilic microorganisms have an absolute requirement for high salt concentration (NaCl concentration). These microbes grow well under the conditions of higher salt concentration but do not survive the lower salt concentrations. For example, the halobacteria are the archaeans that depend on high NaCl concentrations for growth and do not survive at a concentration below about 1.5 M NaCl.

According to the observations, the bacterium could not grow in the tube having a NaCl concentration of 0.5% but exhibits maximum growth under higher NaCl concentrations (15%). This means that the observed bacterium is a halophile or halophilic microbe.

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Explanation:

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Why wouldnt there be any fresh water if water couldnt evaporate
Mariana [72]
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Question 3 (1 point)<br> SC<br> A product of unrestrained nuclear fission is the ________
fenix001 [56]
Sorry but I don’t know
3 0
3 years ago
In a population of cats, the phenotypic frequency of black cats is 91%, and the phenotypic frequency of white cats is 9%. Assumi
Talja [164]

Answer:

1. Allele frequency of b = 0.09 (or 9%)

2. Allele frequency of B = 0.91 (0.91%)

3. Genotype frequency of BB = 0.8281 (or 82.81%)

4. Genotype frequency of Bb = 0.1638 (or 16.38%)

Explanation:

Given that:

p = the frequency of the dominant allele (represented here by B)  = 0.91

q = the frequency of the recessive allele (represented here by b)  = 0.09

For a population in genetic equilibrium:

p + q = 1.0 (The sum of the frequencies of both alleles is 100%.)

(p + q)^2 = 1

Therefore:

p^2 + 2pq + q^2 = 1

in which:  

p^2 = frequency of BB (homozygous dominant)

2pq = frequency of Bb (heterozygous)

q^2 = frequency of bb (homozygous recessive)

p^2 = 0.91^2 = 0.8281

2pq = 2(0.91)(0.9) = 0.1638

4 0
3 years ago
The purpose of mendel's experiments with dihybrid crosses was to determine whether
pshichka [43]

to determine whether traits can be inherited independently

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