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Oksi-84 [34.3K]
3 years ago
13

4.4 + (4 × 14 + 8.6)

Mathematics
2 answers:
Sedaia [141]3 years ago
6 0

4.4 + (4 × 14 + 8.6)

Follow the order of operations (PEMDAS).

4.4+(56+8.6)

4.4+(64.6)

answer: 69

pashok25 [27]3 years ago
6 0
You have to do the parentheses first so you do the multiplication and then additions and then addition outside the parentheses so it would be 69
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Find the outlier in the data: 46, 65, 38, 42, 45, 46, 48, 42. How does the outlier affect the mean? If necessary, round to the n
givi [52]

Answer:

65 is the outlier.  It raises the value of the mean.  42.1

Step-by-step explanation:


5 0
3 years ago
Lian has $1.00 . She has only nickles and dimes. Lian has twice as many dimes and nickles
Lena [83]

Answer:

4 nickels and 8 dimes

Step-by-step explanation:

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5 0
3 years ago
Read 2 more answers
determine the quadratic function of f whose graph is given. The vertex is (1,-3) and the y-intercept is -2
LuckyWell [14K]
Hmmm the y-intercept is at -2?  what does that mean?  well, is where the graph "intercepts" or touches the y-axis, and when that happens, x = 0, so the point is really ( 0 , -2 ).

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\bf \qquad \textit{parabola vertex form}\\\\
\begin{array}{llll}
\boxed{y=a(x-{{ h}})^2+{{ k}}}\\\\
x=a(y-{{ k}})^2+{{ h}}
\end{array} \qquad\qquad  vertex\ ({{ h}},{{ k}})\\\\
-------------------------------\\\\
vertex
\begin{cases}
h=1\\
k=-3
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\textit{now, we also know that }
\begin{cases}
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y=-2
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6 0
3 years ago
Of the 240 sandwiches Joanna makes 20% are tuna sandwiches and 40% are jam sandwiches, and the rest are egg salad sandwiches.How
nikitadnepr [17]
240 = 100%
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4 0
3 years ago
Criterion: Identify IV, DV, and hypotheses and evaluate the null hypothesis for an independent samples t test. Data: Use the inf
Papessa [141]

The table is missing in the question. The table is provided here :

Group 1        Group 2

 34.86            64.14      mean

 21.99            20.46      standard deviation

  7                    7                n

Solution :

a). The IV or independent variable = Group 1

    The DV or the dependent variable = Group 2

b).

  $H_0: \mu_1 = \mu_2$

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  Therefore,   $t = \frac{\bar x_1 - \bar x_2}{\sqrt{\frac{s_1^2}{n_1}+\frac{S_2^2}{n_2}}}$

$t = \frac{34.86 - 64.14}{\sqrt{\frac{21.99^2}{7}+\frac{20.46^2}{7}}}$

t = -2.579143

Now,   $df = min(n_1 - 1, n_2 - 1)$

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Therefore the value of p :

  $=T.DIST(-2.579143,6,TRUE)$

 = 0.020908803

The p value is 0.0209

$p< 0.05$

So we reject the null hypothesis and conclude that $\mu_1 < \mu_2$

7 0
3 years ago
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