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2 years ago

Express cos k as a fraction in simplest terms.

Mathematics

2 answers:

olchik [2.2K]2 years ago

8 0

Answer:

cos K = $\frac{5}{23}$

Step-by-step explanation:

cos K = $\frac{adjacent}{hypotenuse}$ = $\frac{JK}{IK}$ = $\frac{5}{23}$

JulsSmile [24]2 years ago

4 0

Step-by-step explanation:

soh cah toa

that is the saying I use

we will use cah

c is cos

a is ajacent

h is hypotinuse

to find cos K we need to do

adjacent / hypotenuse

can you do that and write it in the comments

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Find the perimeter or cm

kicyunya [14]

Answer:

The perimeter is 22.

Step-by-step explanation:

The perimeter formula (it sometimes varies) is 2(b+h)

b being base (in this example, 6)

h being height (in this example, 5)

So now, with substitution, we are left with:

2(6+5)

Which simplifies down to:

2(11)

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3 years ago

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3 years ago

Find the area of a quadrilateral ABCD in which AB = 3 cm, BC = 4 cm, CD = 4 cm, DA = 5 cm and AC = 5 cm.

melamori03 [73]

Answer:

$6+2\sqrt{21}\:\mathrm{cm^2}\approx 15.17\:\mathrm{cm^2}$

Step-by-step explanation:

The quadrilateral ABCD consists of two triangles. By adding the area of the two triangles, we get the area of the entire quadrilateral.

Vertices A, B, and C form a right triangle with legs $AB=3$ , $BC=4$ , and $AC=5$ . The two legs, 3 and 4, represent the triangle's height and base, respectively.

The area of a triangle with base $b$ and height $h$ is given by $A=\frac{1}{2}bh$ . Therefore, the area of this right triangle is:

$A=\frac{1}{2}\cdot 3\cdot 4=\frac{1}{2}\cdot 12=6\:\mathrm{cm^2}$

The other triangle is a bit trickier. Triangle $\triangle ADC$ is an isosceles triangles with sides 5, 5, and 4. To find its area, we can use Heron's Formula, given by: