Answer:
290
Step-by-step explanation:
If the first term is 2 and the common difference is 32, then the formula for a(n) is:
a(n) = 2 + 32(n-1).
Thus, the 10th term is a(10) = 2 + 32(10-1) = 2 + 32(9) = 290
Answer:
-14r + 6
Step-by-step explanation:
-12r + 6 - 2r
Answer:
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Step-by-step explanation:
Given that;
the frequencies of there alternatives are;
Frequency A = 60
Frequency B = 12
Frequency C = 48
Total = 60 + 12 + 48 = 120
Now to determine our relative frequency, we divide each frequency by the total sum of the given frequencies;
Relative Frequency A = Frequency A / total = 60 / 120 = 0.5
Relative Frequency B = Frequency B / total = 12 / 120 = 0.1
Relative Frequency C = Frequency C / total = 48 / 120 = 0.4
therefore;
CLASS FREQUENCIES RELATIVE FREQUENCIES
A 60 0.5
B 12 0.1
C 48 0.4
TOTAL 120 1
Answer:
yes the answer in 12 fpavers
Step-by-step explanation:
wa
It is 2 and it is 7 the two factors your welcome
