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2 years ago

The sum of 3 consecutive integers is 47 more than the first integer. Find the three integers.

Mathematics

1 answer:

ss7ja [257]2 years ago

7 0

Answer:

22,23,24

Step-by-step explanation:

Well, you need to first find two consecutive integers that add up to 47, because that is the difference between the first digit and the total. This happens to be 23 and 24. Once you get these two numbers, the 22 comes intuitively, as you have to add 23 and 24 to get a difference between 22 and (22+23+24).

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Answer:

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Step-by-step explanation:

Given the rational expression

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Let us first simplify before making our deductions.

Opening the brackets

$\dfrac{7x+5}{x-1} -(\dfrac{8x-1}{x-1} +\dfrac{2x-4}{x-1} )=\dfrac{7x+5}{x-1} -\dfrac{8x-1}{x-1} -\dfrac{2x-4}{x-1}$

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$=\dfrac{7x+5-(8x-1)-(2x-4)}{x-1}$

Opening the brackets and simplifying

$=\dfrac{7x+5-8x+1-2x+4}{x-1}\\\text{Collecting like terms in the numerator}\\=\dfrac{7x-8x-2x+5+1+4}{x-1}\\=\dfrac{-3x+10}{x-1}$

The following statements are therefore true:

2. The denominator of the fully simplified expression will be x – 1.

4. The numerator of the fully simplified expression will be –3x + 10.

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Step-by-step explanation:

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