Which point on the axis satisfies the inequality y<x

Mathematics

1 answer:

Vika [28.1K]2 years ago

6 0

Answer:

every point where x is greater than y or y-x<0

namely, every point below the straight line y=x that cuts the cartesian plane in two

Step-by-step explanation:

You might be interested in

What is 3.341 to the nearest tenth.

Mumz [18]

3.341 to the nearest tenth is 3.3

3 0

3 years ago

Read 2 more answers

What is the product 70 × 10^4? a 70,000 b 700,000 c 280 d 704

weeeeeb [17]

The correct answer is <u>B. 700,000</u>

6 0

2 years ago

The midpoint of the line segment from upper p 1p1 to upper p 2p2 is left parenthesis negative 1 comma 5 right parenthesis(−1,5).

aliya0001 [1]

The coordinates of the second point are (2, 4).

The midpoint formula is:
$m=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})$

Substituting our information, we have:

$(-1, 5)=(\frac{-4+x_2}{2},\frac{6+y_2}{2})$

This means that
$-1=\frac{-4+x_2}{2} \text{ and } 5=\frac{6+y_2}{2}$

Multiply both sides of both equations by 2 to cancel it:
$-1\times2=(\frac{-4+x_2}{2})\times2 \text { and } 5\times2=(\frac{6+y_2}{2})\times2
\\
\\-2=-4+x_2 \text { and } 10=6+y_2
\\-2+4=-4+x_2+4 \text { and } 10-6=6+y_2-6
\\2=x_2 \text{ and } 4=y_2$

This gives us our coordinates (2, 4)

3 0

3 years ago

Find quadratic equation who's roots are 1/2 and -1/3

spin [16.1K]

Answer:

Let's say you have the factored quadratic (x-5)^2=0. The root is just 5, because when you set x-5 to zero and solve for x you have 5. In the same way, we can factor the equation as (x-1/2)(x+1/3), because if you set x-1/2=0 the solution is 1/2. The x+1/3 can also be set to zero and you get -1/3 . Therefore the quadratic has to be (x-1/2)(x+1/3).Foiling this out you get x^2-1/6x-1/6. Note we have to set this equal to zero like the first equation, so the answer is x^2-1/6x-1/6=0

8 0

2 years ago

Determine the growth defined by the equation y=3(3.4)x

jekas [21]

$\bf \qquad \textit{Amount for Exponential Growth}\\\\
A=I(1 + r)^t\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}\\\\
-------------------------------\\\\
\stackrel{A}{y}=\stackrel{I}{3}(3.4)^{x}\implies y=3(1+\stackrel{r}{2.4})^x
\\\\\\
\cfrac{r}{100}=2.4\implies r=100\cdot 2.4\implies r=\stackrel{\%}{240}$

5 0

2 years ago

Which point on the axis satisfies the inequality y<x​

Which point on the axis satisfies the inequality y<x