X=25/11 and y=17/11 if that’s what your asking for
We haven n! = (n-1)! x n and (n+1)! = n! x (n + 1);
Then, (n!)^2 = n! x n! = n! x (n-1)! x n;
And (n+1)!(n-1)! = n! x (n + 1) x (n-1)!;
Finally, [n! x (n-1)! x n] / [n! x (n + 1) x (n-1)!] = (n+1)/n;
Answer:
Explanation:
Identity: sec2θ=1+tan2θ
sec2(π2−x)−1=1+tan2(π2−x)−1
=tan2(π2−x)
Identity: tan(π2−θ)=cotθ
=cot2x
