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Evgen [1.6K]
3 years ago
13

If f(x) = 5x – 3 and g(x) = 3x – 3, find f(x) – g(x). Please include full explanation

Mathematics
2 answers:
Iteru [2.4K]3 years ago
4 0

Answer:

f(x) - g(x) = 2x

Step-by-step explanation:

We have given two functions.

f(x) = 5x-3  and g(x) = 3x-3

We have to find their difference.

f(x)-g(x) = ?

Putting given  values, we have

f(x) - g(x) =( 5x-3) - (3x-3)

Distribute negative sign over second parentheses,

f(x) - g(x) = 5x-3 -(3x)-(-3)

f(x) - g(x) = 5x-3-3x+3

f(x) - g(x) = 5x-3x-3+3

Adding like terms, we have

f(x) - g(x) = 2x+0

f(x) - g(x) = 2x which is the answer.

Kisachek [45]3 years ago
3 0

Answer:

2x

Step-by-step explanation:

f(x) – g(x)

f(x) = 5x – 3 and g(x) = 3x – 3

f(x)- g(x) = 5x – 3 -( 3x – 3)

Distribute the minus sign

               5x -3 -3x+3

Combine like terms

              5x-3x-3+3

               2x

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there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

<h3>How many 2-digit numbers are there in which the tens digit is larger than the ones digit?</h3>

A 2-digit number is written as:

a*10 + b

Where a and b are single-digit numbers.

Tens digit and ones digit refers to place values:

a is the tens digit, and b is the ones digit. The numbers with a larger tens digit than the ones digit are:

98, 97, 96, 95, 94, 93, 92, 91, 90, 87, 86, 85, 84, 83, 82, 81, 80, 76, 75, 75, 74, 73, 72, 71, 70, 65, 64, 63, 62, 61, 60, 54, 53, 52, 51, 50, 43, 42, 41, 40, 32, 31, 30, 21, 20, 10.

We can see that there are 46 numbers in that list, so we conclude that there are 46 2-digit numbers in which the tens digit is greater than the ones digit.

If you want to learn more about place values:

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Answer:

A

Step-by-step explanation:

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Step-by-step explanation:


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