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Elina [12.6K]
3 years ago
11

Solve the equation 3sin2 theta = sin e, for values of e between Oº and 360°

Mathematics
1 answer:
Reil [10]3 years ago
5 0

Answer:

[B] 0, 19.5, 160.5, 180, 360

Step-by-step explanation:

3 sin²θ = sin θ

3 sin²θ − sin θ = 0

sin θ (3 sin θ − 1) = 0

sin θ = 0 or sin θ = ⅓

If sin θ = 0, θ = 0°, 180°, 360°.

If sin θ = ⅓, θ = 19.5°, 160.5°.

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