3 years ago

Solve the equation 3sin2 theta = sin e, for values of e between Oº and 360°

Mathematics

1 answer:

Reil [10]3 years ago

5 0

Answer:

[B] 0, 19.5, 160.5, 180, 360

Step-by-step explanation:

3 sin²θ = sin θ

3 sin²θ − sin θ = 0

sin θ (3 sin θ − 1) = 0

sin θ = 0 or sin θ = ⅓

If sin θ = 0, θ = 0°, 180°, 360°.

If sin θ = ⅓, θ = 19.5°, 160.5°.

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Describe the pattern 0.13, 0.65, 3.25, 16.25

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Let n be the current term and n+1 be the next term

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Keywords: Pattern, Sequence

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