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vitfil [10]
3 years ago
12

Plz help me and show how u got the answer

Mathematics
2 answers:
vladimir1956 [14]3 years ago
5 0
You first want to do the exponent ( PEMDAS )Which equals 16. You then have to multiply 3 and 8 next, due to order of operation which equals 24. Then go left to write, so add 10 to 24, which equals 34. Then subtract 34 from 16. The answer is 18
AlekseyPX3 years ago
4 0
1. mulitply 3 by 8 to get 24.
2. put 4 to the second power to get 16.
3. add 10 plus 24 to get 34.
3. subtract 16 from 34 to get 18.

final answer is 18.

have a great day!!!
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Simplify \sqrt{240}.......
Lesechka [4]

Answer:

4\sqrt{15}

7 0
2 years ago
A triangle has a base of 3 feet, and a height of 6 feet. If its area is increased to 335 ft² by increasing the base and height b
Nonamiya [84]
So you have to find the area, because it says 335 ft². Then add 335 ft ² to the area. The answer is that sum. In otherwords, 9 plus 335
6 0
3 years ago
Solve for x: |x − 2| + 10 = 12
julsineya [31]
1. If x-2≥0,  x≥2
    x-2+10=12
    x+8=12
    x=12-8
    x=4
2.If x-2≤0, x≤2
   -(x-2)+10=12
   -x+2+10= 12
    x = 0
Answer: A)  x=0 and x=4
5 0
3 years ago
Read 2 more answers
Please help me with 1,2,3,4 and show me how you get it the answers
Dafna11 [192]

Answer:

Step-by-step explanation:

Use the formula of distance between the two points (x_1,y_1) and (x_2,y_2),

Distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

1. Distance between A(3, 4) and B(8, 12),

  AB = \sqrt{(8-3)^2+(12-4)^2}

  AB = \sqrt{25+64}

        = \sqrt{89}

        ≈ 9.43

2. Distance between C(-2, 10) and D(3, -2),

   CD = \sqrt{(3+2)^2+(-2-10)^2}

         = \sqrt{25+144}

         = \sqrt{169}

         = 13.00

3. Distance between X(20, 4) and Y(17, 0),

    XY = \sqrt{(20-17)^2+(4-0)^2}

          = \sqrt{3^2+4^2}

          = \sqrt{25}

          = 5.00

4. Distance between E(2, -1) and M(6, 9),

    EM = \sqrt{(2-6)^2+(-1-9)^2}

          = \sqrt{16+100}

          = \sqrt{116}

          = 10.77

8 0
3 years ago
Suppose Global Cable has declared a dividend of $2,500,000. The company has 240,000 shares of preferred stock that pay $2.10 per
Alika [10]

Answer:

$0.7676

Step-by-step explanation:

Dividend declared = $2,500,000.

Total shares of preferred stock = 240,000

Each share costs $2.10

So, Total cost of shares of preferred stock = 240,000×2.10

       Dividend due to the preferred shareholders  = $504,000.

Now,

Total shares of common stock = 2,600,00

Cost of shares of common stocks = Total dividend - Total cost of shares of

                                                                                       preferred stock

                                                           = $2,500,000-504,000

                                                           = $1,996,000

Dividend per share of common stock =$ \frac{1,996,000}{2,600,000}

                                                              = $0.7676                                          

7 0
3 years ago
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