The perimeter of the figure to the nearest hundredth is 50.26 cm.
<h3>Perimeter of a figure.</h3>
The perimeter of a figure is the sum of the whole sides of the figure.
The perimeter of the figure can be found as follows:
perimeter of the figure = 12 + 5 + 5 + circumference of the semi circle
circumference of the semi circle = πr
where
perimeter of the figure = 22 + πr
perimeter of the figure = 22 + 3.14(9)
perimeter of the figure = 22 + 28.26
perimeter of the figure = 50.26 cm
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Split the trapezium into a rectangle and a triangle and work out the areas of them.
4x6=24
(2x4)/2=4
Area of trapezium= 28
There are 2 trapeziums, which makes 56.
The back of the shape is 4x14=56.
The top of the shape is 6x14=84.
The underside of the shape is 8x14=112.
The front rectangle is 14x4.47= 62.58.
As them all together= 56+56+84+112+62.58=370.58.
Total surface area=370.58.
Hope this helps :)
Answer:
x = - 3 and x = 1
Step-by-step explanation:
Given the rational expression
The denominator of the expression cannot be zero as this would make the expression undefined. Equating the denominator to zero and solving gives the values that x cannot be, that is
x² + 2x - 3 = 0 ← in standard form
(x + 3)(x - 1) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 3 = 0 ⇒ x = - 3
x - 1 = 0 ⇒ x = 1
Thus x = 1 and x = - 3 are both excluded values
Hello!
First you have to list the data in both classes
Class A
41, 42, 45, 46, 47, 48, 52, 53, 54, 59, 61, 61, 64, 68, 71, 82, 85, 90
Class B
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
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First we are going to find the mode and mean of class A
The mode is the number that appears the most
The number that appears the most is 61
The mode is 61
To find the mean you add all the numbers together and divide the sum by the amount of numbers added
41 + 42 + 45 + 46 + 47 + 48 + 52 + 53 + 54 + 59 + 61 + 61 + 64 + 68 + 71 + 82 + 85 + 90 = 1069
Divide this by the amount of numbers added
1069 / 18 = 59.3888...
The mean is 59.3888
The mode is 61 and the mean is 59.39 for class A
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We are going to find the range and median for class B
To find the range you subtract the smallest number from the largest on
The smallest number is 41
The largest number is 95
Subtract these
95 - 41 = 54
The range is 54
To find the median you list the numbers from least to greatest and look for the number in the middle
41, 42, 59, 62, 64, 69, 71, 75, 77, 78, 78, 80, 83, 84, 84, 86, 86, 87, 92, 92, 95
The number in the middle is 78
The range is 54 and the median is 78
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Hope this helps!
Answer:
Part a) Exactly values
The width of the rectangle is 
The length of the rectangle is 
Part b) Approximately values
The width of the rectangle is 
The length of the rectangle is 
Step-by-step explanation:
see the attached figure to better understand the problem
we know that
The area of rectangle is equal to
we have
substitute the values in the formula
so
Solve for x
Divide by 4 both sides
square root both sides
The solution is the positive value
therefore
<em>Exactly values</em>
<em>Approximately values</em>
