Simplifique a expressão 10ny-10x+10ny+10y

Mathematics

1 answer:

IRISSAK [1]4 years ago

3 0

Responder:

10 (2ny- (x-y))

Explicación paso a paso:

Dada la expresión 10ny-10x + 10ny + 10y, para simplificar la expresión, se deben seguir los siguientes pasos;

Paso 1; Separa la expresión en términos similares

= 10ny-10x + 10ny + 10y

= (10ny + 10ny) - (10x + 10y)

Paso 2: Factoriza los valores comunes en ambos paréntesis

10ny (1 + 1) - 10 (x-y)

= 10ny (2) - 10 (x-y)

= 20ny - 10 (x-y)

Factoriza nuestro valor común en ambos términos:

= 10 (2ny- (x-y))

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Answer the following true or false. Justify your answer.

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Answer:

a) False b) False c) True d) True e) True

Step-by-step explanation:

a) If A is a subset of B, and x∈B, then x∈A. False

Suppose A is Z (Set of Integers), and B is R (Set of Real Numbers). Then A is a subset of B. x ∈ B, let's say x equals π. If x ∈ B (B = Real Numbers) and x=π then x ∉ A (Z).

We could call A, any other subset of Real numbers (Q, I,..) and we both would come up to the same conclusion when it comes to Real numbers the Set.

So this conclusion is False. Not always an element of a subset is an element of a set.

b) False

For this one, I've drawn some lines, and it is useful to work with them.

Given the set {(x,y) ∈ R²| 0<x<0} then all negative and positive numbers but zero belong to this set.

c) If A and B are square matrices, then AB is also square. True

Taking into account the rules for multiplying matrices. The number of columns of A must be the same number of lines of B to there can be a matrix product.

Whenever we multiply square matrices, we'll always get square matrices. Then this conclusion is true.

d) A and B are subsets of a set S, then A∩B and A∪B are also subsets of S. True

Suppose A= Z (Integer Numbers) and B=Q (Rational Numbers) and S= R (Real Numbers)

A∩B = Z∩Q=∅ and A∪B =Z∪Q = subset

Since the ∅ empty set ⊂ in every set and ZUQ is another Subset of R this is a True conclusion.

e) True. For a matrix A, we define A²= AA

For any Power of Matrices, all we have to do is multiply any given matrix by itself for a given number of times.

M²=M*M

M³=M*M*M