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Brums [2.3K]
4 years ago
7

To play basketball with her friends, Evangeline needs to pump air in her ball, which is completely deflated. Before inflating it

, the ball weighs 0.615 kilograms. Afterwards, it weighs 0.624 kilograms. The diameter of the ball is 0.24 meters.Assuming the inflated ball is perfectly spherical, what is the air density within it.
Mathematics
2 answers:
shtirl [24]4 years ago
6 0

Answer:

1.24 is indeed correct.

Step-by-step explanation:

ZanzabumX [31]4 years ago
4 0

Answer:

1.24 kilograms per cubic meter.

Step-by-step explanation:

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Simplify the expression please help ASAP
Mamont248 [21]

Answer:

maybe answer c/3 or b/2

Step-by-step explanation:

7 0
3 years ago
WILL GIVE BRAINEST <br>which of these is a point slope equation of the line that is.....
gayaneshka [121]
Y - 25 = 2(x-10)
y = 2x - 20 + 25
y = 2x + 5. slope = 2
perpendicular lines, slope is opposite and reciprocal
so slope of perpendicular line is -1/2

passing thru (-3, 7)
point slope form: y - y1 = m (x - x1)

equation
y - 7 = -1/2(x + 3)

answer
B. y - 7 = -1/2(x + 3)
6 0
3 years ago
Derive the equation of the parabola with a focus at (-5,5) and a directix of y = -1
Paladinen [302]

Answer:

D

Step-by-step explanation:

From any point (x, y) on the parabola the focus and directrix are equidistant

Using the distance formula

\sqrt{(x+5)^2+(y-5)^2} = | y + 1 |

Squaring both sides

(x + 5)² + (y - 5)² = (y + 1)^2 , that is

(y + 1)² = (x + 5)² + (y - 5)² ← subtract (y - 5)² from both sides

(y + 1)² - (y - 5)² = (x + 5)² ← expand left side and simplify

y² + 2y + 1 - y² + 10y - 25 = (x + 5)²

12y - 24 = (x + 5)² ← factor left side

12(y - 2) = (x + 5)² ← divide both sides by 12

y - 2 = \frac{1}{12} (x + 5)² ← add 2 to both sides

y = \frac{1}{12} (x + 5)² + 2

or

f(x) = \frac{1}{12} (x + 5)² + 2 → D

7 0
3 years ago
Solve for x and then find the measure of
harkovskaia [24]

Answer:

x = 11

∠B = 80°

Step-by-step explanation:

∠A =∠B because they are corresponding angles

8x - 8 = 5x + 25

3x = 33

divide both sides of the equation by 3:

x = 11

∠B = 5(11) + 25 = 80°

7 0
3 years ago
Find equations of the tangent plane and the normal line to the given surface at the specified point. x + y + z = 8exyz, (0, 0, 8
Dima020 [189]

Let f(x,y,z)=x+y+z-8e^{xyz}. The tangent plane to the surface at (0, 0, 8) is

\nabla f(0,0,8)\cdot(x,y,z-8)=0

The gradient is

\nabla f(x,y,z)=\left(1-8yze^{xyz},1-8xze^{xyz},1-8xye^{xyz}\right)

so the tangent plane's equation is

(1,1,1)\cdot(x,y,z-8)=0\implies x+y+(z-8)=0\implies x+y+z=8

The normal vector to the plane at (0, 0, 8) is the same as the gradient of the surface at this point, (1, 1, 1). We can get all points along the line containing this vector by scaling the vector by t, then ensure it passes through (0, 0, 8) by translating the line so that it does. Then the line has parametric equation

(1,1,1)t+(0,0,8)=(t,t,t+8)

or x(t)=t, y(t)=t, and z(t)=t+8.

(See the attached plot; the given surface is orange, (0, 0, 8) is the black point, the tangent plane is blue, and the red line is the normal at this point)

4 0
3 years ago
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