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aleksley [76]
4 years ago
5

1. For the following quadratic equation, show how both the factoring method and the completing the square method give the same s

olutions. x^2+10x-75=0
2. Write the steps you would use to solve the following quadratic equation. Show two different methods. (x+3)^2=6

Mathematics
1 answer:
enyata [817]4 years ago
4 0
I attached files.
 firstly, I used the factor method to solve the equation and then completing the square method

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The hypotenuse is the side across from the right angle, and it's also the longest side of the triangle.
nalin [4]
Yes You are correct. 
5 0
3 years ago
Read 2 more answers
What is equivalent to 56 − 7 + ( 26 − 4 ) ÷ 2
FrozenT [24]
<h2> 56 − 7 + ( 26 − 4 ) ÷ 2</h2>

<h2>56 - 7 + 22 ÷2</h2>

<h2>56 -7 + 11</h2>

<h2>67 - 7</h2>

<h2>60</h2>
6 0
3 years ago
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I have a really bad grade in Geometry right now and I
Andrews [41]

Answer:  A. (x - 4, y - 2)

               B. (x + 7, y - 11)

<u>Step-by-step explanation:</u>

A) How do you get the x-coordinate of 3 to become a x-coordinate of -1?      by subtracting 4    -->    x - 4

   How do you get the y-coordinate of 5 to become a y-coordinate of 3?      by subtracting 2    -->    y - 2

The transformation is: (x - 4, y - 2)

B)  How do you get the x-coordinate of -4 to become an x-coordinate of 3?     by adding 7    -->    x + 7

    How do you get the y-coordinate of 11 to become a y-coordinate of 0?     by subtracting 11    -->    y - 11

The transformation is: (x + 7, y - 11)

4 0
3 years ago
In the right triangle shown, m∠A = 30 degrees, and BC = 6√2, how long is AC?
mart [117]

They're trying to trick you with √2.  Remember in the 30/60/90 triangle the sides are in ratio 1:√3:2, with the "1" opposite the 30 degrees.

Here we have

1:√3:2  = 6√2:x:hypotenuse

or

x/(6√2) = √3/ 1

x = 6√2×√3 = 6√6

Answer: AC=6√6

3 0
4 years ago
Rename the quadratic function f(x)=-2(x+4)^2-5 in standard form.
Contact [7]

Answer:

function: x=-4

y-intercept: f(0)=-37

Step-by-step explanation:

hope this helps!

8 0
3 years ago
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