Need help with question 4

Mathematics

1 answer:

8090 [49]3 years ago

6 0

Step-by-step explanation:

it's option D (x³)

hope this helps you.

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If an object moving at 1 mile/hour accelerates 1 mile/hour for every meter it travels, how fast will it be travelling in half of

d1i1m1o1n [39]

Answer:

Speed = 0.0003miles/hr

Step-by-step explanation:

Speed of object = 1 mile/hour

For every meter it travels, its acceleration increases by 1 mile/hour

∆Distance = increase in distance

∆speed = 1 meter

The speed and the distance are constant

Speed = distance/time

Time = distance/speed = 1meter/(1 miles/hr)

Convert meter to miles

1609.34 meters = 1mile

1meter = (1meter × 1mile)/(1609.34 meters)

1 meter = (1/1609.34)miles

Time = distance/speed = (1/1609.34)miles/(1 miles/hr)

Time = (1/1609.34)hr

We are to determine the speed the object would be travelling in half of an hour?

In 1hr, it travels (1/1609.34)miles

In ½hr, it travels = (1/1609.34)(½)hr

Speed = 0.0003miles/hr

It will be travelling 0.0003miles/hr in half of an hour

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3 years ago

Find all the points having an x-coordinate of 4 whose distance from the point (-2,-1) is 10

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$A(x_1;\ y_1);\ B(x_2;\ y_2)\\\\the\ distance\ between\ A\ and\ B:\\\\d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\A(-2;-1);\ B(4;\ y);\ d=10\\\\subtitute\\\\\sqrt{(4-(-2))^2+(y-(-1))^2}=10\\\\\sqrt{(4+2)^2+(y+1)^2}=10\\\\\sqrt{6^2+(y+1)^2}=10\\\\\sqrt{36+(y+1)^2}=10\ \ \ |square\ both\ sides\\\\36+(y+1)^2=10^2\\\\36+(y+1)^2=100\ \ \ |subtract\ 36\ from\ both\ sides\\\\(y+1)^2=64\iff y+1=-\sqrt{64}\ or\ y+1=\sqrt{64}\\\\y+1=-8\ or\ y+1=8\ \ \ \ |subtract\ 1\ from\ both\ sides\\\\y=-9\ or\ y=7$

$Answer:{\boxed{(4;-9)\ or\ (4;\ 7)}$

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Solve the following using 2 partial product. 73×23

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70+3
20+3
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73
x 23
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The ratio of deer to foxs was 7 to 3 in the country of New York State. If there were 210 foxes in the country, what was the numb

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