A discontinuity is a point that cannot exist because the x-coordinate would cause a problem in the equation. If you have a polynomial in the denominator, you must find which values of x would cause the polynomial in the denominator to evaluate to zero. Since division by zero is undefined, that would cause a discontinuity.
Let's look at your function.
is in the numerator. It is defined for every value of x. There is no problem there.
is in the denominator. This is a function defined for every value of x, but since it is in the denominator, we must exclude the x-value that would cause this polynomial to evaluate to zero.
We set it equal to zero and solve the equation for x.
For x = 0, the denominator has a value of zero, so at this point there is a discontinuity in function f(x).
The answer is:
If you see that 3x-3 and set it equal to x+7 then you will get this,
3x-3=x+7
Now solve for X. You will get 5.
Then you plug five in and get 12 For both sides and then multiply 12 by 4 and get 48.
You answer is 48.
Hope this helps you.
Answer:
<h3>hope it helps you see the attachment for further information... </h3>
<h3>regards..... </h3>
<h3>_addy_✨✨</h3>
Let's begin by breaking each number down into its prime factors: 4 = 2 x 2 5 = 5 6 = 2 x 3 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4, 5, and 6 by multiplying all common and unique prime factors of each number: common prime factors: 2 unique prime factors: 2,5,3 LCM = 2 x 2 x 5 x 3 = 60 Next, let's determine how many times 60 goes into 10,000 (excluding remainder): 10,000/60 = 166 and 2/3 Multiples of ALL 3 numbers (4,5,6) = 166 Next, let's determine the Lowest Common Multiple (LCM) of the numbers 4 and 5 by multiplying all common and unique prime factors of each number: common prime factors: none
unique prime factors: 2 x 2 x 5
LCM = 2 x 2 x 5 = 20 Next, let's determine how many times 20 goes into 10,000:
10,000/20 = 500
Multiples of BOTH numbers (4 and 5) = 500 Finally, let's subtract the multiples of ALL three numbers (4,5,6) from the multiples of BOTH numbers (4 and 5) to get our answer: Multiples of ONLY numbers 4 and 5 (excluding 6): 500 - 166 = <span>334</span>
Let
a1=1/40
a2=4/40
a3=9/40
a4=16/40
a5=25/40
a6=?
we know that
a2-a1=4/40-1/40----> 3/40
a3-a2=9/40-4/40-----> 5/40
a4-a3=16/40-9/40----> 7/40
a5-a4=25/40-16/40---> 9/40
the difference is
3/40,5/40,7/40.9/40,....
3/40+[2/40]---> 5/40
5/40+[2/40]---> 7/40
7/40+[2/40]---> 9/40
the next will be
9/40+[2/40]-----> 11/40
so
the next term is 25/40+[11/40]------> 36/40
the answer is
36/40
