<em><u>answers</u></em>
y=2×2+3×-1 and x+ y= -1
Step-by-step explanation:
y =2×2+3x-1and x + y =1y= -2×2+3x-7 and x+y=-2x3x-1and x+y =-1
Complete Question
The complete question is shown on the first uploaded image
Answer:
a
Yes the researcher can conclude that the supplement has a significant effect on cognitive skill
b

c
The result of this hypothesis test shows that there is sufficient evidence to that the supplement had significant effect.The measure of effect size is large due to the large value of Cohen's d (0.5778 > 0.30 )
Step-by-step explanation:
From the question we are told that
The sample size is n=16
The sample mean is 
The standard deviation is 
The population mean is 
The level of significance is 
The null hypothesis is 
The alternative hypothesis is
Generally the test statistics is mathematically represented as

=> 
=> 
Generally the p-value is mathematically represented as


From the z-table

=> 
=> 
From the obtained values we see that 
Decision Rule
Reject the null hypothesis
Conclusion
There is sufficient evidence to conclude that the supplement has a significant effect on the cognitive skill of elderly adults
Generally the Cohen's d for this study is mathematically represented as

=> 
=> 
Answer:

Step-by-step explanation:
The y intercept form for the equation of a line is

You should note that <em>c</em> represents the y-intercept of the line (where the line touches the y-axis)

A. True. We see this by taking the highest order term in each factor:

B. True. Again we look at the leading term's degree and coefficient. f(x) behaves like -3x⁶ when x gets large. The degree is even, so as x goes to either ± ∞, x⁶ will make it positive, but multiplying by -3 will make it negative. So on both sides f(x) approaches -∞.
C. False. f(x) = 0 only for x=0, x = 5, and x = -2.
D. False. Part of this we know from the end behavior discussed in part B. On any closed interval, every polynomial is bounded, so that for any x in [-2, 5], f(x) cannot attain every positive real number.
E. True. x = 0 is a root, so f(0) = 0 and the graph of f(x) passes through (0, 0).
F. False. (0, 2) corresponds to x = 0 and f(x) = 2. But f(0) = 0 ≠ 2.
The equation of a circle is written as (x-h)^2 +(y-k)^2 = r^2
h and K are the center points of the circle and r is the radius.
replace the letters with the provided center and radius:
(x- (-7))^2 + (y- (-3))^2 = 2^2
Simplify:
(x+7)^2 + (y+3)^2 = 4