Answer: I think the answer is B
Step-By-Step Explination:
First you find out what x is by doing 42 multiplying it by 0.1 witch equals 4.2 gallons per mile
Next you figure out what y is by doing 4.2y (witch is 4.2 times y)
Suppose the larger pump alone can empty the tank in L hours, and the smaller pump can finish the job in S hours, then each hour the large pump empties 1/L portion of the tank, and the small pump empties 1/S per hour
Working together for three hours, they empty the whole tank, which is 100% of it, so 3/L+3/S=100%=1
Larger pump can empty the tank in 4 hours less than the smaller one, so L=S-4
replace L: 3/(S-4)+3/S=1
Make the denominator the same to solve for:
3S/[S(S-4)] +3(S-4)/[S(S-4)]=1
(3S+3S-12)/[S(S-4)]=1
(3S+3S-12)=[S(S-4)]
S^2-10s+12=0
use the quadratic formula to solve for S
S is about 8.6
The answer is not whole hour.
Answer:
everyone got 6 pieces
Step-by-step explanation:
do you actually need a explanation?
2.47 + 7.1
7.1 + 2.47
9.57-7.1
9.57-2.47
