9514 1404 393
Answer:
9/10
Step-by-step explanation:
(1 1/10) - 1/5 = (1 1/10) -2/10 = 1 + (1/10 -2/10) = 1 -1/10 = 9/10
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1.1 -0.2 = 0.9 = 9/10
Answer:
384 8x8=64 64x2=128 128x3=384
Step-by-step explanation:
Answer: There are 175 pages in the book.
Step-by-step explanation:
If Elena read 20 more pages than Andre and she read 55 pages, to find out how much Andre read you have to:
55-20= the pages Andre read
55-20=35
Andre read 35 pages.
If Andre read 1/5 of the book, then to find how many pages are in the book, you have to multiply 35 x 5. (Multiply by the reciprocal)
35 x 5= 175
There are 175 pages in the book.
To find the answer to this problem, you just need to figure out which total amount of candy is divisible by 7.
161/7=23
<span>162/7=23.1428571429
</span>145/7=<span>20.7142857143
128/7=</span><span>18.2857142857
Obviously, Julie cannot give a fraction of an amount of candy to someone. So that rules out that she had 162, 145, or 128 pieces of candy.
The only amount of candies that Julie could have that is divisible by 7 is 161 candies, which means that 161 is your answer.</span>
Given the following functions below,

Factorising the denominators of both functions,
Factorising the denominator of f(x),

Factorising the denominator of g(x),

Multiplying both functions,