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3 years ago

HELP ASAP PLEASE I DONT WANT TO FAIL

Mathematics

1 answer:

Alla [95]3 years ago

4 0

Answer:

$226.57

Step-by-step explanation:

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I need major help.......................

irakobra [83]

Answer:

0.108

Step-by-step explanation:

0.66 × 0.33 × 0.5 = 0.108.

Formula: L × W × H × 1/6.

L = 4

W = 2

H = 3

4×2×3.

We then have you multiply that by 1/6.

4×1/6 = 0.66.

2×1/6 = 0.33

3×1/6 = 0.5

0.66 × 0.33 × 0.5 = 0.108.

Now, onto the correct answers.

7) (4×1/6cm) × (2×1/6cm) × (3×1/6cm)

7 is correct, because the answer is diving each number by 1/6, and multiplying them with each other.

1) 1/216 × 24

1 is correct, because the answer when the question is evaluated is around 0.108. 1/216 × 24 = 0.11111111111. It is very close to the answer. This, indeed is correct.

7 0

3 years ago

kims age is twice of her sister when you add to her sisters age you get 3 how old is each sister (a) write an equation that repr

Lina20 [59]

Kim is 2. Her sister is 1 years old. 2+1=3

6 0

2 years ago

What is the answer to 2+4(7)-2

Katena32 [7]

Answer:

this is the answer: 28

hope i helped :)

Step-by-step explanation:

5 0

2 years ago

What is 5 3/4 -1 5/12= ?

allsm [11]

Answer:

4.33333333333 or 4 and 1/3

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

The price of a certain computer stock t days after it is issued for sale is p(t)=100+20t−6t^2 dollars. The price of the stock in

Elanso [62]

Answer:

0 < t < $\frac{5}{3}$

After 1.67 days the stocks would be sold out.

Step-by-step explanation:

The price of a certain computer stock after t days is modeled by

p(t) = 100 + 20t - 6t²

Now we will take the derivative of the given function and equate it to zero to find the critical points,

p'(t) = 20 - 12t = 0

t = $\frac{20}{12}$

t = $\frac{5}{3}$ days

Therefore, there are two intervals in which the given function is defined

(0, $\frac{5}{3}$ ) and ( $\frac{5}{3}$ , ∞)

For the interval (0, $\frac{5}{3}$ ),

p'(1) = 20 - 12(1) = 20

For the interval ( $\frac{5}{3}$ , ∞),

p'(2) = 20 - 12(2) = -4

Positive value of p'(t) in the interval (0, $\frac{5}{3}$ ) indicates that the function is increasing.

0 < t < $\frac{5}{3}$

Since at the point t = 1.67 days curve is showing the maximum, so the stocks should be sold after 1.67 days.

7 0

2 years ago