Answer:
114.19186 m
Explanation:
v = Velocity of girl at bottom = 7.1 m/s
= Coefficient of kinetic friction = 0.045
g = Acceleration due to gravity = 9.81 m/s²
d = Distance
N = Normal force = 783 N
The weight of the sled and girl is considered as the sum of the frictional force and weight
Hence we use the following equation where the kinetic energy and potential energy are conserved
The sled travels 114.19186 m on the level ground before coming to a rest
Answer:
27000 Nm
Explanation:
The boom end at A is fixed and end at B is subjected to a 3kN force. Boom AB has length of 9m. The moment about A is the product of force 3kN (3000 N) at B and the moment arm of 9m
M = FL = 3000 * 9 = 27000 Nm
So the moment about A is 27000 Nm
Answer:
there are 3.018 kcal= 3018 cal per gram of candy
Explanation:
If the assume that the calorimeter is perfectly insulated, then all the heat released by the combustion is absorbed by the calorimeter.
Also knowing that Q= C * ΔT , where C= heat capacity of the calorimeter , ΔT= temperature change , Q = heat released by the combustion of the candy
replacing values
Q = C * ΔT = 33.90 kJ/°C * 2.46°C = 83.394 kJ
since Q is the heat released when burned all the mass m of the candy, the number of calories per gram of candy will be
q = Q/m =83.394 kJ / 6.60 g = 12.635 kJ/g
q = 12.635 kJ/g * 1 kcal / 4.186 kJ = 3.018 kcal per gram of candy
Answer:
U = 0 J
Explanation:
Given
N = 180
R = 0.55 m
Iy = 3.4 A
Bx = 1.1 T
U = ?
We can apply the following equation:
U = - μtotal*B*Cos ∅
where
μtotal = N*I*A = N*I*(π*R²) = 180*3.4 A*(π*(0.55 m)²)
⇒ μtotal = 581.603 A*m²
then
U = - (581.603 A*m²)*(1.1 T)*Cos 90º = 0 J
as we know ∅ = 90º
