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3 years ago

A triangle has one angle that measures 29 degrees, one angle that measures 116 degrees, and one angle that measures 35 degrees.

1 answer:

4 0

What is the question? The angles add up to 180, so it is a triangle, however every triangles angles add up to that so there is no specific answer?

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A new computer can complete a complex biochemistry calculation in 7 hours less than an older-model computer. Working together, t

Alchen [17]

The rate a computer works is 1/time. Working together, you add the rates.
Let new computer be x, old computer be y.
x = y - 7

$\frac{1}{x} + \frac{1}{y} = \frac{1}{13} \\ \\ \frac{1}{y-7}+\frac{1}{y} = \frac{1}{13} \\ \\ \frac{2y-7}{y(y-7)} = \frac{1}{13} \\ \\ y(y-7) = 13(2y-7) \\ \\ y^2-33y+91 = 0 \\ \\ y = 29.96 \\ \\ x = y-7 = 29.96-7 = 22.96$
Rounded to nearest tenth gives:
x = 23 hours

6 0

3 years ago

What is 5/10 - 3/20 equal Too?

goldenfox [79]

5/10-30/20 equals 7/ 20

5 0

3 years ago

(I think I know it just checking) Which function has a period equal to half the period of the function in y=5cos(3/5x-pi)+4.. th

eduard

Answer:

A is your answer

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Can I get some help, it is due in 15 minutes and I need help. Thanks, any help appreciated

koban [17]

Well, I'm way past the 15 min mark, but here's how to do the question.

With this, you will need to use the distance formula, $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$ , on XY, YZ, and ZX.

XY: $\sqrt{(3-1)^2+(1-6)^2}$

Firstly, solve inside the parentheses: $\sqrt{(2)^2+(-5)^2}$

Next, solve the exponents: $\sqrt{4+25}$

Next, solve the addition, and XY's distance will be √29

(The process is the same with the other 2 sides, so I'll go through them real quickly)

YZ:

$\sqrt{(6-3)^2+(3-1)^2}\\ \sqrt{(3)^2+(2)^2}\\ \sqrt{9+4}\\ \sqrt{13}$

ZX:

$\sqrt{(1-6)^2+(6-3)^2}\\ \sqrt{(-5)^2+(3)^2}\\ \sqrt{25+9}\\ \sqrt{34}$

Now that we got the 3 sides, we can add them up: $\sqrt{29}+\sqrt{13} +\sqrt{34} =14.8$

In short, your answer is 14.8, or the second option.

8 0

3 years ago

A rectangle swimming pool is 8 feet deep. One side of the pool is 4.5 times longer than the other. The amount of water needed fo

wel

The side lengths of the pool 10 ft and 45 ft.

<u>SOLUTION: </u>

Given, a rectangle swimming pool is 8 feet deep.

One side of the pool is 4.5 times longer than the other.

Let the length of pool be n feet, the width will be 4.5n feet

The amount of water needed for the swimming pool is 3600 cubic ft

We have to find the dimensions of the pool. Now, we know that,

$\begin{array}{l}{\text {volume of pool}=\text {depth} \times \text {length } \times \text {width}} \\\\ {\rightarrow 3600 \text { cubic } f t=8 \text { feet } \times \text { n feet } \times(4.5 n) \text { feet }} \\\\ {\rightarrow 8 n \times 4.5 n=3600} \\\\ {\rightarrow 36 n^{2}=3600} \\\\ {\rightarrow n^{2}=100}\end{array}$

On taking square root on both sides we get,

$\begin{array}{l}{\rightarrow\sqrt{n^{2}}=\sqrt{100}} \\\\ {\rightarrow n=10 \mathrm{ft}}\end{array}$

So, the width will be $4.5 n=4.5 \times 10=45 \mathrm{ft}$

5 0

3 years ago