A pair of sandals is on sale for 65% off the regular price of $8.99. What is the sale price? a. $3.15 b. $4.05 c. $5.84 d. $14.8
2 answers:
You might be interested in
Answer:
Part 1)
Part 2)
Step-by-step explanation:
Step 1
Find the length of MD
we know that
The incenter is the intersection of the angle bisectors of the three vertices of the triangle. Is the point forming the origin of a circle inscribed inside the triangle
so
In this problem
------> is the radius of a circle inscribed inside the triangle
we have that
therefore
Step 2
Find the length of DC
we know that
In the right triangle MDC
Applying the Pythagoras theorem
we have
substitute
The complete question in the attached figure
we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>JD should also subtract the areas of eight hidden surfaces<span>
</span>
we know that
(see the attached figure n 2 to understand the problem)
[the surface area of one prism]=2*[x*x]+2*[x*y]+2*[x*y]----> 2x²+4xy
[the surface area of the sculpture]=2*[5*x*y]+2*[3*x*x]+2*[3*x*y]--> 6x²+16xy
now
<span>JD says the surface area of the sculpture is 4 times the surface area of one prism
</span>[the surface area of the sculpture]=4*(2x²+4xy)---> 8x²+16xy
we compare the value that JD says with the real value
(8x²+16xy) > (6x²+16xy)
the value that JD says is <span>greater in comparison with the real value
</span>This is because <span>JD should also subtract the areas of eight hidden surfaces.
the answer is
</span>JD should also subtract the areas of eight hidden surfaces<span>
</span>