The question is incomplete. Here is the complete question.
Find the measurements (the lenght L and the width W) of an inscribed rectangle under the line y = -
x + 3 with the 1st quadrant of the x & y coordinate system such that the area is maximum. Also, find that maximum area. To get full credit, you must draw the picture of the problem and label the length and the width in terms of x and y.
Answer: L = 1; W = 9/4; A = 2.25;
Step-by-step explanation: The rectangle is under a straight line. Area of a rectangle is given by A = L*W. To determine the maximum area:
A = x.y
A = x(-
)
A = -
To maximize, we have to differentiate the equation:
= 
(-)
= -3x + 3
The critical point is:
= 0
-3x + 3 = 0
x = 1
Substituing:
y = -x + 3
y = -.1 + 3
y = 9/4
So, the measurements are x = L = 1 and y = W = 9/4
The maximum area is:
A = 1 . 9/4
A = 9/4
A = 2.25
The answer for your question is (x,y)=(4,9)
Answer:
b) 8 feet
Step-by-step explanation:
5+3=8
So, the answer will be 8
Answer:
12
Step-by-step explanation:
So, all you have to do is multiply 6 and 2.
In 
If you add + it equals 1 whole.
If 2 equals 1 whole. You multiply 6 by 2.
Hope this helped!
The probability is 4:20
It is correct because there are 20 students and there could be 4 guesses
