3 years ago

Which structure-function pair is mismatched??

Mathematics

1 answer:

Natalija [7]3 years ago

5 0

Where are the pairs. Only one x input must match to 1 y output

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Compare each quotient to its dividend.

frozen [14]

<span>42:6=7, the dividend is 42, the quotient is 7
so 42= 6x7
8:1=8, 8=8x1
12= 1x12
generalization
let be a:b=q, so a = bx q, a dividend, q quotient and b the divisor</span>

4 0

3 years ago

- 4 + x = 120 find the variable?

mafiozo [28]

Answer:

X = 124

Step-by-step explanation:

-4+x=120

We move all terms to the left:

-4+x-(120)=0

We add all the numbers together, and all the variables

x-124=0

We move all terms containing x to the left, all other terms to the right

x=124

7 0

3 years ago

Suppose that PR=47. Solve for x and find the lengths of PQ, and QR.

Troyanec [42]

Answer:

×=7, pq=27, qr=20.

Step-by-step explanation:

(4x-1)+(3x-1)=47 therefore 7x-2=47 or 7x=49 and x=7, pq=4x-1=27, qr=3x-1=20.

6 0

4 years ago

Find the measures of the interior angles.

Leona [35]

Where is the question?

6 0

2 years ago

Perform the indicated operation and state the domain. Let f(x) = 3x^1/3 and g(x) = 2x^1/2 Express as (f+g)(x)

lana [24]

Answer:

$(f + g)(x) = 3x^{\frac{1}{3}}+2x^{\frac{1}{2}}$

$x \ge 0$

Step-by-step explanation:

Given

$f(x) = 3x^{\frac{1}{3}}$

$g(x) = 2x^{\frac{1}{2}}$

Solving (a): (f + g)(x)

In functions:

$(f + g)(x) = f(x) + g(x)$

So, we have:

$(f + g)(x) = 3x^{\frac{1}{3}}+2x^{\frac{1}{2}}$

Solving (b): The domain of f(x)

For (f + g)(x) to be defines, the value of x must be greater than or equal to 0.

Hence, the domain is:

$x \ge 0$

4 0

3 years ago