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saw5 [17]
3 years ago
13

Suppose that PR=47. Solve for x and find the lengths of PQ, and QR.

Mathematics
1 answer:
Troyanec [42]3 years ago
6 0

Answer:

×=7, pq=27, qr=20.

Step-by-step explanation:

(4x-1)+(3x-1)=47 therefore 7x-2=47 or 7x=49 and x=7, pq=4x-1=27, qr=3x-1=20.

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