Write in standard form y =

You guys help me please I’m stuck

DanielleElmas [232]

The answer should be $40

6 0

4 years ago

Write in exponential form: 4*4*4*4*4 Use the ^ to indicate an exponent.

Misha Larkins [42]

4,5 bc it’s 5 fours

7 0

3 years ago

Triangles and algebra

Elanso [62]

Hello from MrBillDoesMath!

Answer:

x = 10

Discussion:

A plane triangle contains 180 degrees. Adding the angles in the triangle shown in #8 gives

(4x + 7) + (3x + 13) + 90 = 180

Note the "right angle" shown in the triangle has been replaced by its 90 degree equivalent in the above equation.

Combining like terms gives

( 4x + 3x) + (7 + 13) + 90 = 180

7x + 20 + 90 = 180 => (subtract 90 from each side)

7x + 20 + 90 - 90 = 180 - 90 = 90 =>

7x +20 = 90 => (subtract 20 from each side)

7x + 20 -20 = 90 -20 =>

7x = 70 =>

x 70/7 =10.

Thank you,

MrB

3 0

4 years ago

Professor Jennings claims that only 35% of the students at Flora College work while attending school. Dean Renata thinks that th

lisov135 [29]

Answer:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

Step-by-step explanation:

Information given

n=78 represent the random sample taken

X=36 represent the students with jobs

$\hat p=\frac{36}{78}=0.462$ estimated proportion of students with jobs

$p_o=0.35$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the proportion of students with jobs is higher than 0.35, the system of hypothesis are:

Null hypothesis: $p \leq 0.35$

Alternative hypothesis: $p > 0.35$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.462 -0.35}{\sqrt{\frac{0.35(1-0.35)}{78}}}=2.074$

Now we can calculate the p value with this probability:

$p_v =P(z>2.074)=0.019$

If we use a significance level os 0.05 we see that the p value is lower than the significance level so then we can conclude that the true proportion of students with jobs is higher than 0.35 for this case. If we decrease the significance level to 1% the result changes otherwise not.

5 0

4 years ago

Help please it’s due tomorrow.

____ [38]

What so you need to know?

8 0

3 years ago

Write in standard form y = - 4x + 5