All categories

3 years ago

What is the solution set for the open sentence with the given replacement set y2 -3=y+ [0,1,3,4]

1 answer:

7 0

It is three cuz when replace with three it is all equal:
3(2)-3=3
6-3=3
3=3
please rate as brainliest and hope this helps :)

You might be interested in

Which of the following has a value CLOSEST to 0.5?

KengaRu [80]

9514 1404 393

Answer:

D) 6.003 ÷ 12

Step-by-step explanation:

All of the quotients differ from 0.5 by at least one order of magnitude except ...

6.003/12 = 0.50025

The others are ...

A: 0.301/60 = 0.0050166... (repeating)

B: 0.051/10 = 0.0051

C: 2.499/49 = 0.051

5 0

3 years ago

Given That ABCD is a rhombus, what is the value of x?

3241004551 [841]

5x - 18 + x = 90

6x = 108

x = 18 degrees

8 0

3 years ago

Read 2 more answers

|9-(-1)|= simplify the expression

Hitman42 [59]

Answer:

Step-by-step explanation:

Remove parentheses.

|9+1|

Simplify 9+1 to 10.

|10|

simplify

7 0

3 years ago

Can someone help me with this problem

Alex_Xolod [135]

Answer:

Step-by-step explanation:

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

A(-3, 0) , B(3, 2)

$AB=\sqrt{(3-(-3))^2+(2-0)^2}=\sqrt{6^2+2^2}=\sqrt{36+4}=\sqrt{40}=\sqrt{4\cdot10}=\sqrt4\cdot\sqrt{10}=2\sqrt{10}$

A(-3, 0), D(-2, -3)

$AD=\sqrt{(-2-(-3))^2+(-3-0)^2}=\sqrt{1^2+(-3)^2}=\sqrt{1+9}=\sqrt{10}$

AB = CD and AD = BC

The area of a rectangle:

$A=(AB)(AD)$

Substitute:

$A=(2\sqrt{10})(\sqrt{10})=(2)(10)=20$

The perimeter of a rectangle:

$P=2(AB+AD)$

Substitute:

$P=2(2\sqrt{10}+\sqrt{10})=2(3\sqrt{10})=6\sqrt{10}$

4 0

3 years ago

Here is a picture of a cube, and the net of this cube.

natali 33 [55]

Hdosnduhx 572cm uwu thsjwkqo iwhsbei dc usb
Twhen usb I ze have 6382cm soaped 720
Wheel ah Wiriirue Shan 8391xm

5 0

3 years ago