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3 years ago

11,760,825 in word format

Mathematics

1 answer:

stepan [7]3 years ago

6 0

Eleven million, seven hundred sixty thousand, eight hundred twenty five

Hope this helps!

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A store had 1000 glasses. Each month, 10% of the glasses are sold. If it continued for each month, the store keeper can predict

spin [16.1K]

I dont know sorry but im sure sonmeone else can help you im reallu sorry

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3 years ago

Elissa owns 28% of the grumman corporation. the rest of the shares are owned equally by the remaining six shareholders. what per

skad [1K]

100%-28= 72 divide by 6 = 12% each

6 0

3 years ago

Read 2 more answers

What is the product? (5r + 2)(3r − 4)

Anarel [89]

Distribute the first set of parenthesis

15r2−20r+6r−8
Combine like terms

15r2+(−20r+6r)−8
Simplify your answer

15r2−14r−8

*Answer is 15r^2−14r−8*

6 0

3 years ago

The U.S. Department of Agriculture records data on farm acreage and number of farms by county for every county in the country. T

lisabon 2012 [21]

Solution :

From the table,

Number of countries = $N_i$

Mean = $\overline Y_i$

Standard deviation = $\sigma_i$

Margin of error of B = 50,000 acres

So we determine the $\text{sample size n}$ and then allocate the four regions of $n_1, n_2, n_3$ and $n_4$ .

Under the $\text{proportional allocation}$ , the $\text{equation}$ for the value of $n_1$ which yields $V(\overline Y_{st}) = D = \frac{B^2}{H}$ is given by :

$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$

Let us complete the numerator

$\sum_{K=1}^L N_K \sigma^2_K = N_1\sigma_1^2 + N_2\sigma_2^2 + N_3\sigma_3^2 + N_4\sigma_4^2$

$= 1052 \times (271)^2 + 210 \times (79)^2 + 1376 \times (244)^2 + 418 \times (837)^2$

= 453329920

The bound on the error of estimation is B = 50,000 acres

Hence we get

$D=\frac{B^2}{H}$

$=\frac{50000^2}{4}$

= 625,000,000

$n=\frac{\sum_{K=1}^L N_K \sigma^2_K}{ND+\frac{1}{N}\sum_{K=1}^L N_K \sigma^2_K}$

$=\frac{453329920}{3056 \times 625 + \frac{1}{3056} \times 453329920}$

= 220.24044

≈ 221 (approximately)

Therefore, the sample size under the proportional allocation from each stratum are given by :

$n_1=n\left[\frac{N_1}{\sum_{K=1}^\mu N_K}\right]$

$=221\left[\frac{1052}{3056}\right]$

≈ 76

$n_2=n\left[\frac{N_2}{\sum_{K=1}^\mu N_K}\right]$

$=221\left[\frac{210}{3056}\right]$

≈ 15

$n_3=n\left[\frac{N_3}{\sum_{K=1}^\mu N_K}\right]$

$=221\left[\frac{1376}{3056}\right]$

≈ 100

$n_4=n\left[\frac{N_4}{\sum_{K=1}^\mu N_K}\right]$

$=221\left[\frac{418}{3056}\right]$

≈ 30

Thus, we should select 76 counties from North central region, 15 counties from the north east region, 100 from south region and 30 from west region.

We can also estimate mean acreage of each county across all the county with a margin of error of 50,000 acres.

8 0

3 years ago

In the function f(x) = 2x + 3, x is the dependent variable. True or false

klemol [59]

Answer:

true

Step-by-step explanation:

not 100% sure but I had a question similar a few years back.

4 0

3 years ago