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vekshin1
2 years ago
13

Find the area of the regular polygon 10, 4

Mathematics
1 answer:
Afina-wow [57]2 years ago
3 0
With all the given context, I would assume it’s length times width, which would give us an answer of 40 :) hope this helped !
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Who knows how to do this
Oksi-84 [34.3K]

Answer:

(-1, 7)

Step-by-step explanation:

2 unites left would movie from 1 to -1.

1 unit down would move from 8 to 7.

7 0
3 years ago
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Suppose y varies jointly as x and z. Find y when x=-9 and z=23, if y=117 when x=-3 and z=-11. Round your answer to the nearest h
Andrew [12]

Answer:

The value of y given the values of x and z in the question is -734.85

Step-by-step explanation:

This is a joint variation question.

First, we are made to know that y varies jointly as x and z.

The equation for this can be written as;

y = k * x * z

Where k is the constant of proportionality.

Let’s calculate k first.

117 = k * (-3) * (-11)

33k = 117

K = 117/33 = 3.55

Now, we proceed to get what y is when x = -9 and z = 23

Let’s plug these values into the initial equation written.

y = k * x * z

We use the value of k calculated above;

y = 3.55 * (-9) * (23) = -734.85

4 0
3 years ago
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6(3x - 2) + 5(x + 6)
andreyandreev [35.5K]

Answer:

x=3.5

Step-by-step explanation:

1. Multiply

18x-12=5x+30

2.  Move the x's to one side

12x= 42

3. Isolate the variable by dividing

x=3.5

7 0
3 years ago
Can you please tell me asp
Lera25 [3.4K]

Answer:

i think 8

Step-by-step explanation:

5 0
3 years ago
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Combine each pair of equations solve the combined equation 3j +14=-5z-10j=5z
ArbitrLikvidat [17]

Given data:

The first equation is 3j +14=-5z.

The second equation is -10j=5z​ .

Add both the equations.

\begin{gathered} (3j+14)+(-10j)=-5z+5z \\ -7j+14=0 \\ 7j=14 \\ j=2 \end{gathered}

Substitute 2 for j in the first equation.

\begin{gathered} 3(2)+14=-5z \\ 20=-5z \\ z=-4 \end{gathered}

Thus, the value of j is 2 and z is -4.

3 0
1 year ago
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