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Natasha_Volkova [10]
3 years ago
6

What is the y-intercept of y+4=-1/4(x+2)

Mathematics
2 answers:
Hunter-Best [27]3 years ago
6 0
Get the equation in slope-intercept form.

y + 4 = -\frac{1}{4}(x + 2)
y = -\frac{1}{4}(x + 2) - 4
y = -\frac{1}{4}x - \frac{1}{2} - 4
y = -\frac{1}{4}x -4.5

The y-intercept is (0, -4.5).


m_a_m_a [10]3 years ago
4 0
Y + 4 = -1/4(x + 2)
y + 4 = -1/4x - 1/2
y = -1/4x - 4 1/2

y intercept is at (0, -4 1/2 )
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–6 + 4k = 2(–2k + 5) + 6k
balu736 [363]

Answer:

k=8

Step-by-step explanation:

yes

5 0
3 years ago
Toby wants to find the volume of a solid toy soldier.
mr Goodwill [35]

Answer:

Toby wants to find the volume of a solid toy soldier.He fills a rectangular container 8 cm long, 6 cm wide,and 10 cm high with water to a depth of 4 cm. Toby totally submerges the toy soldier in the water. The height of the water with the submerged toy soldier is 6.6 cm. Which of the following is closest to the volume, in cubic centimeters, of the toy soldier?

A. 125 B. 156 C. 192 D. 208 E.317

The volume of the toy is 125 cubic cm ,option A is the closest answer.

Step-by-step explanation:

Given:

A rectangular container .

Length of the container =8 cm

Width of the container = 6 cm  

Height of the container when water is filled = (h_1) = 4 cm

Height of the container when the toy is submerged = (h_2) =6.6 cm

Volume of the toy =  Volume of the container with the toy - Volume of the container (with water)

Volume of the toy = (l\times b\times h_2) - (l\times b\times h_1)

                              = (l\times b\times)(h_2-h1)

                              = (6\times 8)(6.6-4)

                              = 48\times 2.6

                              = 124.8 cubic centimeters.

So,the closest value to the volume of the toy is 125 cubic centimeters.

6 0
3 years ago
Which equation represents the line that passes through (5,8) and (9,2)
Dahasolnce [82]
ASSUMING This is a straight line so we gotta the formula for a straight line which is y=mx+b, where m represents the slope and b represents the y intercept.

First, we know this line passes through (5,8) and (9,2) we can use these for finding the equations. When we know two points, we use this formula:

y-y=m(x-x)

The first y is 8 and the second one is 2
The first x is 5 and the second one is 9

Plug it in:

8-2=m(5-9)
6=m(-4)
6/-4=m <— simplify this
m= -3/2

*NOTE: another way to find m is by calculating it (y-y)/(x-x)

Now we know m, we have to find b.
All you gotta do is plug everything you know back into the equation y=mx+b

y=mx+b
y=-3/2x+b <— now plug in a point we know(x,y)

8=-3/2(5)+b
8=-15/2+b
8-(-15/2)=b
b=8+15/2
b=16/2+15/2
b=31/2 (now you can write be as a fraction or a decimal in your equation, depending on what your teacher told you to use)
*NOTE: it is best to use fractions instead of decimals as it is more accurate sometimes.

Now we know all the variables that need to be known, we just need to rewrite the formula of the equation so the teacher can see.

m=-3/2
b=31/2

We don’t need to plug in x or y since it could have different values (since a straight line has MANY co-ordinates)

SO OUR EQUATION IS=
y=(-3/2)x+31/2

Hope you understand this, feel free to ask me anything!

6 0
3 years ago
What is the type of association between variables x and y?
Molodets [167]

Answer:

strong negative correlation

Step-by-step explanation:

if x goes up y goes down and if y goes up x comes down

8 0
3 years ago
Evaluate the integral by making an appropriate change of variables.
VARVARA [1.3K]

By inspecting the integrand, the "obvious" choice for substitution would be

<em>u</em> = <em>y</em> + <em>x</em>

<em>v</em> = <em>y</em> - <em>x</em>

<em />

Solving for <em>x</em> and <em>y</em>, we would have

<em>x</em> = (<em>u</em> - <em>v</em>)/2

<em>y</em> = (<em>u</em> + <em>v</em>)/2

in which case the Jacobian and its determinant are

J=\begin{bmatrix}x_u&x_v\\y_u&y_v\end{bmatrix}=\dfrac12\begin{bmatrix}1&-1\\1&1\end{bmatrix}\implies|\det J|=\left|\dfrac12\right|=\dfrac12

The trapezoid <em>R</em> has two of its edges on the lines <em>x</em> + <em>y</em> = 8 and <em>x</em> + <em>y</em> = 9, so right away, we have 8 ≤ <em>u</em> ≤ 9.

Then for <em>v</em>, we observe that when <em>x</em> = 0 (the lowest edge of <em>R</em>), <em>v</em> = <em>y</em> ; similarly, when <em>y</em> = 0 (the leftmost edge of <em>R</em>), <em>v</em> = -<em>x</em>. So

-<em>x</em> ≤ <em>v</em> ≤ <em>y</em>

-(<em>u</em> - <em>v</em>)/2 ≤ <em>v</em> ≤ (<em>u</em> + <em>v</em>)/2

-<em>u</em> + <em>v</em> ≤ 2<em>v</em> ≤ <em>u</em> + <em>v</em>

-<em>u</em> ≤ <em>v</em> ≤ <em>u</em>

<em />

So, the integral becomes

\displaystyle\iint_R5\cos\left(7\frac{y-x}{y+x}\right)\,\mathrm dA=\int_8^9\int_{-u}^u\frac52\cos\left(\frac{7v}u\right)\,\mathrm dv\,\mathrm du

=\displaystyle\frac52\int_8^9\frac u7(\sin7-\sin(-7))\,\mathrm du

=\displaystyle\frac57\sin7\int_8^9u\,\mathrm du

=\displaystyle\frac5{14}\sin7(9^2-8^2)=\boxed{\frac{85}{14}\sin7}

4 0
3 years ago
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