Ask question

Ask question

All categories

Svetllana [295]

2 years ago

7

What is 0.5 of 44.18

1 answer:

Bess [88]2 years ago

8 0

Answer:

22.09

Step-by-step explanation:

0.5 of 44.18

of also means multiplication

so we're going to multiply 0.5 by 44.18

ie, 0.5×44.18=22.09

You might be interested in

Pls guys help me pls

galina1969 [7]

Answer:

$x < 5$

I think the answer is A

8 0

2 years ago

PLEASE HELP!!!!

stira [4]

"The total number of stamps is 35" is the statement among the following choices given in the question that is correct. The correct option among all the options that are given in the question is the third option or the penultimate option. I hope that this is the answer that has actually come to your great help.

7 0

3 years ago

Read 2 more answers

How do you solve this linear systems of equations?<br> x+3y−z=24<br> x+2y+5z=13<br> x+z=12

ale4655 [162]

I hope this helps you

6 0

2 years ago

M + 3n = 7 ; n = -2, 0 , 1

tiny-mole [99]

Step-by-step explanation:

for rhis question are u tryna find m?

4 0

3 years ago

Read 2 more answers

Triangle ABC has AB=5, BC=7, and AC=9. D is on AC with BD=5. Find the length of DC

e-lub [12.9K]

Answer:

$DC=\frac{8}{3}\ units$

Step-by-step explanation:

The picture of the question in the attached figure

we know that

The triangle ABD is an isosceles triangle

because

AB=BD

The segment BM is a perpendicular bisector segment AD

so

<em>In the right triangle ABM</em>

Applying the Pythagorean Theorem

$BM^2=AB^2-AM^2$

we have

$AB=5\ units\\AM=x\ units$

substitute

$BM^2=5^2-x^2$

$BM^2=25-x^2$ -----> equation A

<em>In the right triangle BMC</em>

Applying the Pythagorean Theorem

$BM^2=BC^2-MC^2$

we have

$BC=7\ units\\MC=AC-AM=(9-x)\ units$

substitute

$BM^2=7^2-(9-x)^2$

$BM^2=49-(81-18x+x^2)$

$BM^2=49-81+18x-x^2$

$BM^2=-x^2+18x-32$ ----> equation B

equate equation A and equation B

$-x^2+18x-32=25-x^2$

solve for x

$18x=25+32\\18x=57\\\\x=\frac{57}{18}$

Simplify

$x=\frac{19}{6}$

<em>Find the length of DC</em>

$DC=AC-2x$

substitute the given values

$DC=9-2(\frac{19}{6})$

$DC=9-\frac{19}{3}\\\\DC=\frac{8}{3}\ units$

8 0

3 years ago