Answer:

Step-by-step explanation:
see the attached figure with letters to better understand the problem
we know that
In the right triangle ABD

In the right triangle BCD

remember that
m< BAD=m<CBD
therefore

equate the equations



I'm confused what are you suppose to do
Answer:
good news, the second one is relatively easy because it can be factored to (2x+1)(2x-3) which means that number two has solutions of -1/2 and 3/2
but for number one you have to either use the quadratic equation cause I've tried using synthetic division or just use the second equation to derive the first solutions so I tried move the graph up by two units and found that the intercepts are approximately (1+-√2)/2 or 1/2+-1/√2 for 4x^2-4x-1
I believe the formula is lxwxh if so it's 20 x 30 x 4= 2400 i hope this helped
Given:

First, let us find two points from this equation.
We can set values of x and then solve for y.
Let us find the values of y when x = 1, 2, 3, 4, 5

We now have a set of points:
(1, 21)
(2, 16)
(3, 11)
(4, 6)
(5, 1)
Since the given plane is limited to values of 10 and -10, the points that we can plot are the points (4, 6) and (5, 1)
The graph would then look like this: