Answer:
Therefore there total of 39 children presented in group of people who attended a ball game.
Step-by-step explanation:
Given:
Total people present=52 .
And there are 3 times children as adults
To Find:
No.of Children Present in Group.
Solution:
<em>Consider 'x' be the children and 'y' be Adults presented in group.</em>
<em />
So there are total of 52 people.
Therefore Equation becomes,
x+y=52.
And also there are 3 times children presented in group as adults were.
So
Children=3 times adults
i.e.x=3y
Using in above Equation we get ,
x+y=52
3y+y=52
4y=52
y=52/4
y=13
Hence there are 13 adults presented in group
So ,
No.of Children=x=3y
=3(13)
=39
No.of.Children =39
Answer:
Total taxes = $1,520
Step-by-step explanation:
We have two separate calculations for the taxes:
The tax rate for the first $5,000 of Clarisa's gross pay is 1%, so the amount of tax paid in this case is
1% * 5000 = $50
The tax rate for the amount of value over $5,000 (that is, 54,000 - 5,000 = 49,000) is 3%, so the amount of tax is:
3% * 49,000 = $1,470
So, the total amount deducted for state taxes is:
Total taxes = 50 + 1470 = $1,520
Answer:
The margin of error M.O.E = 2.5%
Step-by-step explanation:
Given that;
The sample size = 1500
The sample proportion
= 0.60
Confidencce interval = 0.95
The level of significance ∝ = 1 - C.I
= 1 - 0.95
= 0.05
The critical value:
(From the z tables)
The margin of error is calculated by using the formula:




M.O.E = 0.02479
M.O.E ≅ 0.025
The margin of error M.O.E = 2.5%
Answer:
0.75 cents
Step-by-step explanation:
You take...
$2.25 and subtract $1.50 to get 0.75 cents
In-depth...
Start off with taking a dollar away...
2.25 - 1.00 = 1.25
Then take off 0.50 cents...
We know that 0.50 cents are two 0.25 cents
So, we take off one 0.25 cent
1.25 - 25 = 1.00
Then the next 0.25 cents
*Remember: twenty-five (.25), fifty (.50), seventy-five (.75), a dollar (1.00)
<--- it is just adding 25 each time
If we subtract 0.25 cents from a dollar we get...
0.75 cents
A value that "lies outside" (is much smaller or larger than)