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Olin [163]
3 years ago
15

Which of the following is true about the expression square root of 3*2

Mathematics
1 answer:
baherus [9]3 years ago
7 0

Answer:

B

Step-by-step explanation:

\sqrt{3}*2=3.464101615137755‬ so it is equal to an irrational number.

2 is rational, and \sqrt{3} is irrational, because it is equal to 1.732050807568877‬

Hope this helps you. Please mark brainliest! Have a nice day!

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Step-by-step explanation:

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3/7 p= -6<br> solve for p!<br> please help!
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p = -6 * 7 / 3 = -14


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M is a degree 3 polynomial with m ( 0 ) = 53.12 and zeros − 4 and 4 i . Find an equation for m with only real coefficients (i.E.
Nitella [24]

Answer:

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

Step-by-step explanation:

Given that M is a polynomial of degree 3.

So, it has three zeros.

Let the polynomial be

M(x) =a(x-p)(x-q)(x-r)

The two zeros of the polynomial are -4 and 4i.

Since 4i is a complex number. Then the conjugate of 4i is also a zero of the polynomial i.e -4i.

Then,

M(x)= a{x-(-4)}(x-4i){x-(-4i)}

      =a(x+4)(x-4i)(x+4i)

      =a(x+4){x²-(4i)²}      [ applying the formula (a+b)(a-b)=a²-b²]

      =a(x+4)(x²-16i²)

      =a(x+4)(x²+16)      [∵i² = -1]

      =a(x³+4x²+16x+64)

Again given that M(0)= 53.12 . Putting x=0 in the polynomial

53.12 =a(0+4.0+16.0+64)

\Rightarrow a = \frac{53.12}{64}

      =0.83

Therefore the required polynomial is

M(x)=0.83(x³+4x²+16x+64)

5 0
3 years ago
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