Can I get help on this please someone

Mathematics

2 answers:

Aleonysh [2.5K]3 years ago

4 0

Answer:

Step-by-step explanation:

Let's break down the definitions.

Supplementary = degrees add up to 180

Vertical = share a common vertex

Complementary = degrees add up to 90

Adjacent = share a common side and vertex

Since the degrees add up to 90 and don't share a common side/vertex, the angles are complementary.

Musya8 [376]3 years ago

3 0

Answer:

I think the answer is C

You might be interested in

PLEASE HELP

lisabon 2012 [21]

Step-by-step explanation:

The figure below shows a portion of the graph of the function $j\left(x\right) \ = \ 4^{x-2}$ , hence the average rate of change (slope of the blue line) between the $x$ and $x+h$ is

$\text{Average rate of change} \ = \ \displaystyle\frac{\Delta y}{\Delta x} \\ \\ \rule{3.7cm}{0cm} = \dsiplaystyle\frac{f\left(x+h\right) \ - \ f\left(x\right)}{\left(x \ + \ h \right) \ - \ x} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{f\left(x + h\right) \ - \ f\left(x\right)}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x+h-2} \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{4^{x-2+h} \ - \ 4^{x-2}}{h}$

$\\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h}\right) \ - \ 4^{x-2}}{h} \\ \\ \\ \rule{3.7cm}{0cm} = \displaystyle\frac{\left(4^{x-2}\right)\left(4^{h} \ - \ 1 \right)}{h}$

7 0

1 year ago

I need to find all real values of x from this inequality x^2>2x-2 and also this question x^2>2x+2. I need the answer fast

sergeinik [125]

$x^2\gt2x-2$

$x^2-2x+2\gt0$

You are essentially asking at this point where is the quadratic function greater than 0. To get the interval find the roots. Between the roots the function is guaranteed to be LESS THAN zero. Everywhere else the function is greater than 0.

$x^2-2x+2=0$

Use Vieta's rule to get the roots,

$(x-1)(x-1)=0$

Both roots are the same so no value is less than 0 which means all values except at the point of root are strictly greater, the point of root is at $x_{1,2}=1$ which means the set for which the quadratic function is greater than 0 is $\mathbb{R}-\{1\}$ "all real numbers except 1".