Question

How would i solve A & B?

Answer 1

Answer:

$\large\boxed{a)\ A\approx93.53\ in^2}\\\boxed{b)\ 8,640\ in^2}$

Step-by-step explanation:

a)

The formula of an area of a regular hexagon:

$A=6\cdot\dfrac{a^2\sqrt3}{4}$

a - side length

We have a = 6in. Substitute:

$A=6\!\!\!\!\diagup^3\cdot\dfrac{6^2\sqrt3}{4\!\!\!\!\diagup_2}=3\cdot\dfrac{36\!\!\!\!\!\diagup^{18}\sqrt3}{2\!\!\!\!\diagup_1}=3\cdot18\sqrt3=54\sqrt3\ in^2\\\\A\approx93.53\ in^2$

b)

$5ft=5(12in)=60in\\\\12ft=(12)(12in)=144in$

The area of a hallway:

$A=(60)(144)=8,640\ in^2$