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LenaWriter [7]
3 years ago
9

The first two steps in determining the solution set of the system of equations, y = x2 – 6x + 12 and y = 2x – 4, algebraically a

re shown in the table.Which represents the solution(s) of this system of equations? (4, 4) (–4, –12) (4, 4) and (–4, 12) (–4, 4) and (4, 12)
Mathematics
2 answers:
olchik [2.2K]3 years ago
3 0

Answer:

y = 2x - 4....so sub in 2x - 4 for x in the other equation

y = x^2 - 6x + 12

2x - 4 = x^2 - 6x + 12

x^2 - 6x - 2x + 12 + 4 = 0

x^2 - 8x + 16 = 0

(x - 4)(x - 4) = 0

x - 4 = 0

x = 4

x - 4 = 0

x = 4

solution is (4,4)

(2, −1) and (−4, 17)

Step-by-step explanation:

DedPeter [7]3 years ago
3 0

Answer:

wrong up top

Step-by-step explanation:

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saul85 [17]

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5 0
3 years ago
Someone plz help this is due today
-Dominant- [34]

3x+5x+1=17

x=2

y=5•2+1

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(x, y)=(2, 11)

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