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LenaWriter [7]
3 years ago
9

The first two steps in determining the solution set of the system of equations, y = x2 – 6x + 12 and y = 2x – 4, algebraically a

re shown in the table.Which represents the solution(s) of this system of equations? (4, 4) (–4, –12) (4, 4) and (–4, 12) (–4, 4) and (4, 12)
Mathematics
2 answers:
olchik [2.2K]3 years ago
3 0

Answer:

y = 2x - 4....so sub in 2x - 4 for x in the other equation

y = x^2 - 6x + 12

2x - 4 = x^2 - 6x + 12

x^2 - 6x - 2x + 12 + 4 = 0

x^2 - 8x + 16 = 0

(x - 4)(x - 4) = 0

x - 4 = 0

x = 4

x - 4 = 0

x = 4

solution is (4,4)

(2, −1) and (−4, 17)

Step-by-step explanation:

DedPeter [7]3 years ago
3 0

Answer:

wrong up top

Step-by-step explanation:

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At a hot dog stand they serve regular hot dogs and footling hot dogs at a ratio of 5 to 3. Based on this ratio how many footlong
natta225 [31]
Answer:
45
Step-by-step explanation:
Ratio is 5:3
So total ratio "parts" is 5 + 3 = 8
In total there are 120 dogs served, so each part is:
120/8 = 15 dogs
Since, footlong hot dogs are "3" parts, and each part is 15 dogs, there will be:

3 * 15 = 45 footlong hotdogs
3 0
3 years ago
What is the best and easiest method to use to find sides A and B?
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what is the best and easiest method to use to find sides A and B?

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3 years ago
Find the partial fraction decomposition of the rational expression with prime quadratic factors in the denominator
SpyIntel [72]
\dfrac{5x^4-7x^3-12x^2+6x+21}{(x-3)(x^2-2)^2}=\dfrac{a_1}{x-3}+\dfrac{a_2x+a_3}{x^2-2}+\dfrac{a_4x+a_5}{(x^2-2)^2}
\implies 5x^4-7x^3-12x^2+6x+21=a_1(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(a_4x+a_5)(x-3)

When x=3, you're left with

147=49a_1\implies a_1=\dfrac{147}{49}=3

When x=\sqrt2 or x=-\sqrt2, you're left with

\begin{cases}17-8\sqrt2=(\sqrt2a_4+a_5)(\sqrt2-3)&\text{for }x=\sqrt2\\17+8\sqrt2=(-\sqrt2a_4+a_5)(-\sqrt2-3)\end{cases}\implies\begin{cases}-5+\sqrt2=\sqrt2a_4+a_5\\-5-\sqrt2=-\sqrt2a_4+a_5\end{cases}

Adding the two equations together gives -10=2a_5, or a_5=-5. Subtracting them gives 2\sqrt2=2\sqrt2a_4, a_4=1.

Now, you have

5x^4-7x^3-12x^2+6x+21=3(x^2-2)^2+(a_2x+a_3)(x-3)(x^2-2)+(x-5)(x-3)
5x^4-7x^3-12x^2+6x+21=3x^4-11x^2-8x+27+(a_2x+a_3)(x-3)(x^2-2)
2x^4-7x^3-x^2+14x-6=(a_2x+a_3)(x-3)(x^2-2)

By just examining the leading and lagging (first and last) terms that would be obtained by expanding the right side, and matching these with the terms on the left side, you would see that a_2x^4=2x^4 and a_3(-3)(-2)=6a_3=-6. These alone tell you that you must have a_2=2 and a_3=-1.

So the partial fraction decomposition is

\dfrac3{x-3}+\dfrac{2x-1}{x^2-2}+\dfrac{x-5}{(x^2-2)^2}
7 0
3 years ago
What is 5x minus 5 factored​
AveGali [126]

Answer:

5(x-1)

Step-by-step explanation:

5 0
3 years ago
Ami'yan runs every day for exercise at a rate of 1 kilometer every 15 minutes. How many meters does he run in 1 hour? - Thank yo
Alona [7]

Answer:

The total distance covered in 1 hour  is 4000 meters.

Step-by-step explanation:

The distance Ami'yan runs is 15 minutes = 1 kilometer

Using the unit formula,

The distance ran in 1 minute = (\frac{1}{15} ) \textrm{Kilometer}

Now, 1 hour = 60 minutes

⇒The distance covered in 60 minutes =  60 x (Distance run in 1 minute)

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So, the distance covered in 1 hour  = 4 kilometer

1 kilometer = 1000 meters

⇒ 4 km =  4 x 1000 meters = 4000 m

Hence, the total distance covered in 1 hour  = 4000 meters.

6 0
3 years ago
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