The first two steps in determining the solution set of the system of equations, y = x2 – 6x + 12 and y = 2x – 4, algebraically a re shown in the table.Which represents the solution(s) of this system of equations? (4, 4) (–4, –12) (4, 4) and (–4, 12) (–4, 4) and (4, 12)
2 answers:
Answer:
y = 2x - 4....so sub in 2x - 4 for x in the other equation
y = x^2 - 6x + 12
2x - 4 = x^2 - 6x + 12
x^2 - 6x - 2x + 12 + 4 = 0
x^2 - 8x + 16 = 0
(x - 4)(x - 4) = 0
x - 4 = 0
x = 4
x - 4 = 0
x = 4
solution is (4,4)
(2, −1) and (−4, 17)
Step-by-step explanation:
Answer:
wrong up top
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