Answer:
20 masks and 100 ventilators
Step-by-step explanation:
I assume the problem ask to maximize the profit of the company.
Let's define the following variables
v: ventilator
m: mask
Restictions:
m + v ≤ 120
10 ≤ m ≤ 50
40 ≤ v ≤ 100
Profit function:
P = 10*m + 65*v
The system of restrictions can be seen in the figure attached. The five points marked are the vertices of the feasible region (the solution is one of these points). Replacing them in the profit function:
point Profit function:
(10, 100) 10*10 + 65*100 = 6600
(20, 100) 10*20 + 65*100 = 6700
(50, 70) 10*50 + 65*70 = 5050
(50, 40) 10*50 + 65*40 = 3100
(10, 40) 10*10 + 65*40 = 2700
Then, the profit maximization is obtained when 20 masks and 100 ventilators are produced.
Since we have to divide 60 by ¾, so get 60/ ¾ =60* 4/3 = 80
15x + 28y = 116
x + y = 6
that would be ur system of equations
Answer:
I will: Multiply 32 times 20 to get the total cost of the foods and tickets. Then I will add the total cost of the tickets and the total cost of the bus to get the total cost of the trip. Lastly I will divide the total cost of the trip by 2 to find out how much money the class need to earn.
Solution: 32 • 20 = 640 + 900 = 1,540 ÷ 2 = 770
Answer: 770