Answer:
V = $3.50t + $90.5....
Step-by-step explanation:
V(t) is a function of t that expresses the value in year 2000+t.
We know that the increase is $3.50 times t.
So,
V(t) = $3.50t + c
where c is the constant.
V(15) = $3.50 (15) + c = $143 [t=15 as mentioned in the question]
and therefore
c = $143 - $3.50 (15)
c= $143 - $52.50
c= $90.5
Now we got the value of c. We can write the equation as
V = $3.50t + $90.5....
Answer:
4c + 15
Step-by-step explanation:
THIS IS THE COMPLETE QUESTION BELOW;
A department store's customer parking lot has 4 rows with an equal number of parking spots in each row. The lot also has 15 parking spots for store employees. If c cars can be parked in each of the 4 main rows of the parking lot, what is the expression for the maximum number of cars that can be parked in the parking lot?
15c − 4
c(15 − 4)
4c + 15
4(c + 15)
✓We were told that the customer stores parking has Total number of 4 rows,
✓ for " c" cars to be parked in the 4 main rows i.e in each of them, we can calculate the overall numbers of car parked in the rolls as ( 4 × c)= 4c
✓ we were told that there are 15 parking spots available to employees in the store
✓ maximum number of cars that can fit into the parking lot will be ( 15 + 4c)
= 4c + 15
Answer:
50%
Step-by-step explanation:
the will have 75minis 25
Answer:
518
i don't know if this needs much explaining.
