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Naily [24]
3 years ago
11

Evaluate (a + b)2 for a = 2 and b = 3

Mathematics
2 answers:
pogonyaev3 years ago
8 0
10 because (2+3)2 we would do PEMDAS and get to (5)2 which is 10 :) hope this helped
Ivenika [448]3 years ago
5 0

f(a,b) = 2(a+b)

f(2,3) = 2(2+3)

f(2,3) = 2(5)

f(2,3) = 10

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What is 200 miles in 5 hours in unit rate?
aleksley [76]
200 miles in 5 hours in unit rate is 200/5 which would equal <span>40 miles in each 1 hour. </span>
8 0
4 years ago
Maisie is watching a movie she has been watching for 36 minutes there are 55 minutes to go how long does the movie last .let m
geniusboy [140]

Answer:

Step-by-step explanation:

m= movie time

m=36+55=19 minutes

3 0
3 years ago
A submarine travels N45 W 16 miles. It then turns a course of 216 measured clockwise off of due north and travels until it is du
lozanna [386]

Answer:

19.5 miles

Step-by-step explanation:

The question is represented in the image attached.

∠A = 45°, ∠B = 45° + (216° - 180°) = 81°

∠A + ∠B + ∠C = 180° (sum of angles in a triangle)

45° + 81° + ∠C = 180°

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∠C = 180 - 126

∠C = 54°

The sine rule states that for a triangle with sides a, b, c and their corresponding opposite angles A, B and C. The following rule holds:

\frac{a}{sin(A)}= \frac{b}{sin(B)}= \frac{c}{sin(C)}

b = length of beginning of submarine to end point. Using sine rule:

\frac{b}{sin(81)} =\frac{16}{sin(54)} \\\\b=\frac{16}{sin(54)}*sin(81)\\\\b=19.5\ miles

7 0
3 years ago
Can someone help me with these five problems please i will mark as brainliest if the answers are correct
kondaur [170]

Answer:

1. C

2. B

3. C

4. A

5. D

Step-by-step explanation:

4 0
3 years ago
Given that SQ¯¯¯¯¯ bisects ∠PSR and ∠SPQ≅∠SRQ, which of the following proves that PS¯¯¯¯¯≅SR¯¯¯¯¯?
yanalaym [24]

Step-by-step explanation:

It is given that ∠SPQ≅∠SRQ

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles S P Q and S R Q are highlighted in red.

It is also given that SQ⎯⎯⎯⎯⎯

bisects ∠PSR

.

By the definition of angle bisector, ∠PSQ≅∠QSR

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are congruent and highlighted in red.

△PQS

and △RQS share a common side SQ⎯⎯⎯⎯⎯, and SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

by the Reflexive Property of Congruence.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Segment S Q is highlighted in red.

Two angles, ∠SPQ

and ∠PSQ, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △PQS are congruent to two angles, ∠SRQ and ∠QSR, and a nonincluded side, SQ⎯⎯⎯⎯⎯, of △RQS

.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Angles P S Q and R S Q are highlighted in red. Angles S P Q and S R Q are highlighted in red. Side S Q is highlighted in blue.

So, △PQS≅△RQS

by the Angle-Angle-Side (AAS) Congruence Theorem.

PS⎯⎯⎯⎯⎯

and SR⎯⎯⎯⎯⎯ are corresponding sides of congruent triangles, △PQS and △RQS. So, PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

by CPCTC.

The figure shows the same triangles P Q S and R Q S as in the beginning of the task. Sides S R and S P are congruent and highlighted in red.

Translate these six statements and reasons into a 2

-column proof,

1. ∠SPQ≅∠SRQ

(Given)

2. SQ⎯⎯⎯⎯⎯

bisects ∠PSR

. (Given)

3. ∠PSQ≅∠QSR

(Def. of ∠

bisect)

4. SQ⎯⎯⎯⎯⎯≅SQ⎯⎯⎯⎯⎯

(Reflex. Prop. of ≅

)

5. △PQS≅△RQS

(AAS Steps 1, 3, 4)

6. PS⎯⎯⎯⎯⎯≅SR⎯⎯⎯⎯⎯

(CPCTC)

There you go

4 0
3 years ago
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