OM=18, so OQ=QM=18/2=9.
Given QU=8
from figure OQU is a right angled triangle , so OU^2=OQ^2 + QU^2
OU^2 = 9*9 + 8*8 = 81+72=153;
OU=sqrt(153) = 12.37 =13(approx);
From given statements of congruent NT and OU will also be congruent or identical. So, NT=OU=13
Formula for the area of a circle is Pi*radius squared
So, we do Pi*2^2 which is 12.57
Answer:
<h2>x = 6 cm</h2>
Step-by-step explanation:
think we hve to use trigonometry here
sin 30⁰
see the pic
sorry I am from India and we solve this type of sum with this method
There is an app that could help u out a lot is called MathPapa
(3-4x)(8+3x)
= (3+-4x)(8+3x)
= (3)(8)+(3)(3x)+(-4x)(8)+(-4x)(3x)
= 24+9x-32x-12x^2
= -12x^2-23x+24
