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Maru [420]
3 years ago
15

Your friend has improved in his math class. On his first test he scored 50 points, and then he scored 53, 56, 59, and 62 points

on his next 4 tests. His tests continued to improve following this pattern. If he took 15 tests, how many points did he score on the last test?
Mathematics
1 answer:
emmainna [20.7K]3 years ago
3 0

Answer:

Step-by-step explanation: I think you skip count by 50s or something like that. So, it has to be 64.

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11

Step-by-step explanation:

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Which equations have the same value of x as Three-fifths (30 x minus 15) = 72? Select three options.
lozanna [386]

The equivalent expressions are 3(6x - 3) = 72 and 18x - 9 = 72

<h3>Equations and expressions</h3>

Given the equation below as shown;

3/5(30x - 15) = 72

Expand

3/5(30x) - 3/5(15) = 72

90x/5 - 15/5 = 72

3(6x - 3) = 72

Expand

18x - 9 = 72

Hence the equivalent expressions are 3(6x - 3) = 72 and 18x - 9 = 72

Learn more on equations here: brainly.com/question/13763238

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5 0
2 years ago
A rectangular banner on the school office wall is 45 inches tall and 70 inches long. A photograph of the banner for the yearbook
Umnica [9.8K]

45 |   45 divided by 5 = 9    

So i think if we do the same for 70 we will get the length

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So the length = 14

--If I'm incorrect please correct me

5 0
3 years ago
Find the sum
lakkis [162]

Answer:

Numerator = 2(b^2+a^2)    or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

Step-by-step explanation:

Let

S = 2b/(b+a)^2 + 2a/(b^2-a^2)   factor denominator

= 2b/(b+a)^2 + 2a/((b+a)(b-a))     factor denominators

= 1/(b+a) ( 2b/(b+a) + 2a/(b-a))    find common denominator

= 1/(b+a) ((2b*(b-a) + 2a*(b+a))/((b+a)(b-a))   expand

= 1/(b+a)(2b^2-2ab+2ab+2a^2)/((b+a)(b-a))  simplify & factor

= 2/(b+a)(b^2+a^2)/((b+a)(b-a))  simplify & rearrange

= 2(b^2+a^2)/((b+a)^2(b-a))

Numerator = 2(b^2+a^2)    or equivalently 2b^2+2a^2

Denominator = (b+a)^2*(b-a), or equivalently b^3+ab^2-a^2b0-a^3

4 0
3 years ago
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