Answer:
Number of points, x, Number of segments, y
x: 2, 3, 4, 5, ... N,. ...
y: 1, 3, 6, 10, ... (N-1)(N)/2, ...
Step-by-step explanation:
Adding Nth point, there are N-1 new segments,
and (sum over {i = 1 to N-1} of i) total segments. As Gauss knew when he was c.10 yo, the sum is (N-1)(N)/2.
He have about 0 dime and 69 coins each
Answer:
W is either 4, 5, 6, or 7.
Step-by-step explanation:
1
Simplify \frac{1}{2}\imath n(x+3)21ın(x+3) to \frac{\imath n(x+3)}{2}2ın(x+3)
\frac{\imath n(x+3)}{2}-\imath nx=02ın(x+3)−ınx=0
2
Add \imath nxınx to both sides
\frac{\imath n(x+3)}{2}=\imath nx2ın(x+3)=ınx
3
Multiply both sides by 22
\imath n(x+3)=\imath nx\times 2ın(x+3)=ınx×2
4
Regroup terms
\imath n(x+3)=nx\times 2\imathın(x+3)=nx×2ı
5
Cancel \imathı on both sides
n(x+3)=nx\times 2n(x+3)=nx×2
6
Divide both sides by nn
x+3=\frac{nx\times 2}{n}x+3=nnx×2
7
Subtract 33 from both sides
x=\frac{nx\times 2}{n}-3x=nnx×2−3
(x+6)2+(y-10)2=36 , would be your equation.
